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Answer:
the probability that the exceeded 65 = 0.3707
The average score of the 36 golfers exceeded 65
= 36 X 0.3707 = 13.3452
Step-by-step explanation:
<u>Step 1</u>:-
The average score of all golfers for a particular course has a mean of 64 and a standard deviation of 3.
mean (μ) = 64
standard deviation (σ) =3
by using normal distribution
given (μ) = 64 and (σ) =3
i) when x =65
P( X≥ 65) = P(z≥0.33)
= 0.5 - A(z₁)
= 0.5 - 0.1293 (see normal table)
= 0.3707
The average score of the 36 golfers exceeded 65
= 36 X 0.3707 = 13.3452
Answer:
464 grams.
Step-by-step explanation:
Amount of substance:
The amount of substance after t years is given by an equation in the following format:
In which A(0) is the initial amount and r is the decay rate, as a decimal.
Co-60 has a half life of 5.3 years.
This means that:
We use this to find r. So
So
If a pellet that has been in storage for 26.5 years contains 14.5g of Co-60, how much of this radioisotope was present when the pellet was put in storage?
We have that , and use this to find A(0). So
[tex]A(0) = 464[tex]
464 grams.