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Y_Kistochka [10]
3 years ago
6

Which of the following is not a triangle congruence theorem? A) ASA B) AAS C) SSA

Mathematics
2 answers:
Maurinko [17]3 years ago
6 0

Answer:

<em>C. SSA</em><em> is the only one which is not a triangle congruence theorem.</em>

Step-by-step explanation:

Triangle congruence-

When two triangles are congruent they will have exactly the same three sides and exactly the same three angles.

Two triangles can be proven to be congruent by the following postulates,

  1. SAS (Side-Angle-Side)
  2. SSS (Side-Side-Side)
  3. ASA (Angle-Side-Angle)
  4. AAS (Angle-Angle-Side)
  5. RHS (Right-angle-Hypotenuse-Side)

Therefore, from the given options SSA is the only one which is not a triangle congruence theorem.

serg [7]3 years ago
3 0
Don't listen to them asa is a very real thing! It's the angle side angle!! It would be C! Ssa! That doesn't exist!
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If an=5n-3 find the common difference​
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Answer:

Hi here is your answer

an=5n-3

an-1= -3+5n

an-1= -3+5(n-1)

an-1= -3+5n-5

an-1= 5n-7

d= an- an-1

d=(5n-3)-(5n-7)

d=5n-3-5n+7

d=4

Answer: d = 4

Hope this helps you.

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Answer:

Sure. Whats the question.?

Step-by-step explanation:

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3 years ago
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kiruha [24]

Answer:

mean for a = 60/10 = 6

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mean for b = 80/10 = 8

mad of b = 2

Step-by-step explanation:

Mean absolute deviation (MAD) of a data set is the average distance between each data value and the mean. Take each number in the data set, subtract the mean, and take the absolute value. Then take the sum of the absolute values. Now compute the mean absolute deviation by dividing the sum above by the total number of values in the data set. The mean absolute deviation, MAD, is 2.

\frac {1}{n} \sum \limits_{i=1}^n |x_i-m(X)|

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2 years ago
Suppose that the universal set is U={1,2,3,4,5,6,7,8,9,10}. Express each of the following subsets with bit strings (of length 10
Vladimir [108]

Answer:

0011100000

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Step-by-step explanation:

As the question is not complete, Here is the complete question.

Suppose that the universal set is U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Express each of these sets with bit strings where the ith bit in the string is 1 if i is in the set and 0 otherwise.

a) {3, 4, 5}

b) {1, 3, 6, 10}

c) {2, 3, 4, 7, 8, 9}.

So, we need to express a) b) and c) into bit strings.

Firstly, number of elements in the universal set represent the number of bits in the bit string.

Secondly, 1 = yes element is present in both universal set as well as in sub set.

0 = No, element is not present in sub set but present in universal set.

Hence, we have:

a) Sub set {3,4,5} = 0011100000  (As there are 3 1's which means only 3,4,5 are present in both universal set and subset.

Similarly,

b) Sub set {1, 3, 6, 10} = 1010010001

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What is the answer to 5+5=
HACTEHA [7]
The answer to 5+5 is 10
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