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3 years ago

A. What is the total number of valence electrons in the polyatomic ion of Ammonium? 5, 6, 7, 8, 10

Chemistry

1 answer:

Mamont248 [21]3 years ago

8 0

Answer:

Explanation:

Ammonium ion $(NH_4)^+$ is formed when ammonia $(NH_3)$ reacts with hydrogen ion $H^+$

$NH_3+H^+=NH_4^+$

In $NH_4^+$ the nitrogen has 5 valence electron and there are 4 hydrogen each has 1 valence electron

So total number of valence electron =4+5=9

But $NH_4^+$ has 1 positive charge on it, it means it losses 1 electron

So total number of valence electron in poly atomic ion of $NH_4^+$ is 9-1=8

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The assumptions made in calculating the Michaelis-Menten Equation include

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Answer:

c) that the formation and decomposition of ES is the same for a period of time

Explanation:

Michaelis-Menten equation :

This model explain the approach to enzyme kinetics.The Equation shows how a Free enzyme E and Product P is formed depicting by Following equation.

E+S⇌ES→E+P

Left side represents

E =enzyme

S=substrate

ES=enzyme-substrate complex

Right side

E= Free enzyme

P= product

c) that the formation and decomposition of ES is the same for a period of time

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4 years ago

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3 years ago

Read 2 more answers

The equilibrium constant in terms of pressure. Kp for the following process is 0.179 at 50 °C. It increases to 0.669 at 86 °C. C

Vikentia [17]

Answer:

a) ΔHvap=35.3395 kJ/mol

b) Tb=98.62 °C

Explanation:

Given the reaction:

C₇H₁₆ (l) ⇔ C₇H₁₆ (g)

Kp=P(C₇H₁₆) since the concentration ratio for a pure liquid is equal to 1.

When

T₁=50°C=323.15K ⇒P₁=0.179

T₂=86°C=359.15K ⇒P₂=0.669

The Clasius-Clapeyron equation is:

$ln(\frac{P_2}{P_1}) =-\frac{AH_{vap}}{R} (\frac{1}{T_2}-\frac{1}{T_1})$

$ln(\frac{0.669}{0.179}) =-\frac{AH_{vap}}{8.3145 J.mol^{-1}K^{-1}} (\frac{1}{359.15K}-\frac{1}{323.15K})$

$1.3184 =-\frac{AH_{vap}}{8.3145 J.mol^{-1}K^{-1}} (-3.10186*10^{-4}K{^-1})$

ΔHvap=35339.5 J/mol=35.3395 KJ/mol

Normal boiling point ⇒ P=1 atm

Hence, we find the normal boiling point where:

T₁=323.15K

P₁=0.179 atm

P₂=1 atm

$ln(\frac{P_2}{P_1}) =-\frac{AH_{vap}}{R} (\frac{1}{T_2}-\frac{1}{T_1})$

$ln(\frac{1atm}{0.179atm}) =-\frac{35339.5 J/mol}{8.3145 J.mol^{-1}K^{-1}} (\frac{1}{T_2}-\frac{1}{323.15K})$

$1.7203=-4250.34 (\frac{1}{T_2}-\frac{1}{323.15K})$

T₂=371.77 K= 98.62 °C

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3 years ago

Which of the following statements about the ordinary IR spectroscopic regions are TRUE? 1. In general, the IR FUNDAMENTAL region

yaroslaw [1]

Answer: the statements in 1 and 2 are true of IR spectroscopic region.

1. In general, the IR FUNDAMENTAL region has a longer wavelength region than the region we call the ultraviolet (uv) region.

2. We can sense some of the frequencies of the FUNDAMENTAL region of the IR as heat

Explanation:

IR has energy value between 10^-5eV - 10^-2eVwhile

UV has energy value of 4eV - 300eV

IR has low photon energy and cannot alter atoms and molecules while UV has sufficient energy to iodize atoms therefore UV has a higher energy band.

Infrared light falls just outside the visible spectrum, beyond the edge of what we can see as red.

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3 years ago

Chlorine is a very reactive non-metals. Why

Vadim26 [7]

Answer:

Chlorine is a very reactive non metals because this element don't form any known chemical compound.

Explanation:

Chlorine atoms have a lot of valance electrons without being complete on its own, so it has a greater need to seek it's conjugates. That's called electronegativity. Halogens are highly reactive because of their electronegativity.

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3 years ago