The oxidizing agent is the one that is reduced which is also the one who gains electron. The reducing agent is the one that is oxidized which is also the one who loses electron. Thus,
a. The substance H2S is the one oxidized.
b. The substance I2 is the one reduced.
c. The oxidizing agent is I2.
d. The reducing agent is H2S.
In covalent bonding, both atoms are trying to attract electrons--the same electrons. Thus, the electrons are shared tightly between the atoms.
The force of attraction that each atom exerts on the shared electrons is what holds the two atoms together.
Answer:
heat rate= 1281W
length = 15.8m
Explanation:
we have this data to answer this question with
Tmi = 85 degrees
Tmo = 35 degrees
Ts = 25 dgrees
flow rate = 25 degrees
using engine oil property from table a-5
Tm = Tmo - TMi/2 = 333k
u =0.522x10⁻²
k = 0.26
pr = 51.3
cp = 2562 J/kg.k
mcp(Tmo-Tmi) =
0.01 x 2562(35-85)
= 1281 W
we find the change in Tim
= [(35-25)-(85-25)]/ln[(35-25)/(85-25)]
= -50/ln0.167
= -50/-1.78976
= 27.9°c
we finf the required reynold number
4x0.01/πx0.003x0.522x10⁻²
= 0.04/0.00004921
= 812.8
= 813
we find approximate correlation
NuD = hd/k
NuD = 3.66
3.66 = 0.003D/0.26
cross multiply
0.003D = 3.66x0.26
D = 3.66x0.26/0.003
= 317.2
As = 1281/317x27.9
= 0.145
As = πDL
L = As/πD
= 0.145/π0.003
= 0.145/0.009429
L = 15.378
Answer:
The mole fraction is the number of moles of something divided by the number of total moles present. First, let us work out the number of moles of KCl present. A 26.3% w/w solution would contain 26.3 g of KCl per 100 g of solution. Hence, 26.3 g of KCl is 26.374.5513 = 0.353 moles
Explanation:
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