The answer is A I’m not 100 percent sure tho
Hey there!:
Molar mass of Mg(OH)2 = 58.33 g/mol
number of moles Mg(OH)2 :
moles of Mg(OH)2 = 30.6 / 58.33 => 0.5246 moles
Molar mass of H3PO4 = 97.99 g/mol
number of moles H3PO4:
moles of Mg(OH)2 = 63.6 / 97.99 => 0.649 moles
Balanced chemical equation is:
3 Mg(OH)2 + 2 H3PO4 ---> Mg3(PO4)2 + 6 H2O
3 mol of Mg(OH)2 reacts with 2 mol of H3PO4 ,for 0.5246 moles of Mg(OH)2, 0.3498 moles of H3PO4 is required , but we have 0.649 moles of H3PO4, so, Mg(OH)2 is limiting reagent !
Now , we will use Mg(OH)2 in further calculation .
Molar mass of Mg3(PO4)2 = 262.87 g/mol
According to balanced equation :
mol of Mg3(PO4)2 formed = (1/3)* moles of Mg(OH)2
= (1/3)*0.5246
= 0.1749 moles of Mg3(PO4)2
use :
mass of Mg3(PO4)2 = number of mol * molar mass
= 0.1749 * 262.87
= 46 g of Mg3(PO4)2
Therefore:
% yield = actual mass * 100 / theoretical mass
% = 34.7 * 100 / 46
% = 3470 / 46
= 75.5%
Hope that helps!
Answer:
yes the ones u chose are correct.
Explanation:
The lithosphere, hydrosphere, and atmosphere are the abiotic parts of the planet.
Answer:
, the solution is basic
Explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
Acids have pH ranging from 1 to 6.9 and bases have pH ranging from 7.1 to 14.Neutral substances have pH of 7.
![pH=-\log [H_3O^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH_3O%5E%2B%5D)
![pOH=-\log[OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%5BOH%5E-%5D)
Putting in the values:
![pOH=-\log[5.5\times 10^{-5}]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%5B5.5%5Ctimes%2010%5E%7B-5%7D%5D)



![9.8=-\log [H_3O^+]](https://tex.z-dn.net/?f=9.8%3D-%5Clog%20%5BH_3O%5E%2B%5D)
![[H_3O^+]=1.6\times 10^{-10}M](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%3D1.6%5Ctimes%2010%5E%7B-10%7DM)
As pH is more than 7, the solution is basic