I think we can use the identity sin x/2 = sqrt [(1 - cos x) /2]
cos x - sqrt3 sqrt ( 1 - cos x) /sqrt2 = 1
cos x - sqrt(3/2) sqrt(1 - cos x) = 1
sqrt(3/2)(sqrt(1 - cos x) = cos x - 1 Squaring both sides:-
1.5 ( 1 - cos x) = cos^2 x - 2 cos x + 1
cos^2 x - 0.5 cos x - 0.5 = 0
cos x = 1 , -0.5
giving x = 0 , 2pi, 2pi/3, 4pi/3 ( for 0 =< x <= 2pi)
because of thw square roots some of these solutions may be extraneous so we should plug these into the original equations to see if they fit.
The last 2 results dont fit so the answer is x = 0 , 2pi Answer
Answer:
Therefore the value of bond will triple after 17.72 years.
Step-by-step explanation:
The formula of Compounded continuously
A= Amount after t year
P= initial amount
r = rate of interest
t= time in year.
Given that,
Jacobs college saving are invested in bond that pay 6.2% compounded continuously.
Let after t years the initial amount P will be triple i.e 3P.
Here P=P, A=3P, r= 6.2%=0.062
[ Multiply 
both sides]
Taking ln both sides
[ since 
]
years
Therefore the value of bond will triple after 17.72 years.
The mode is 85, because it is the most occurring in the data set.
hope that helps :)
Answer:
interest: $60
Payment: $360
Step-by-step explanation:
I = Prt
Interest for four years = 300 * 0.05 * 4 = 60
P = P₁ + I = 300 + 60 = 360
