Write an equation that passes through (2,4) is parallel to the line 3x-2y=-10
1 answer:
Answer:
y = 3x/2 + 3
Step-by-step explanation:
First let's solve for y in the given equation
Subtract 3x from both sides
3x - 2y = -10
- 3x - 3x
-2y = -3x - 10
Divde both sides by -2
-2y/-2 = (-3x - 10)/-2
y = 3x/2 + 5
The slop of the parallel equation will have to be 3/2
y = 3x/2 + b
Plug in the given coordinates
4 = 3(2)/2 + b
4 = 1 + b
Subtract 1 from both sides
4 = 1 + b
- 1. - 1
b = 3
y = 3x/2 + 3
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