All categories

3 years ago

16-2n-5+8n=65 Can you help me solve this please and show work as well?

2 answers:

8 0

∙•❁ Okay time to solve this Step-By-Step.❁•∙ 

16−2n−5+8n=65

∙•❁ So the first part we need to Simplify both sides of this equation, so:

16−2n−5+8n=65

∙•❁ We are going to simplify this Step-By-Step.

16−2n−5+8n=65

16+−2n+−5+8n=65

∙•❁ Combine like terms:

(−2n+8n)+(16+−5)=65 

6n+11=65

6n+11=65

∙•❁ Now subtract 11 from both sides.

6n+11−11=65−11

6n=54

∙•❁ Now divide both sides by 6 and you'll get your answer:

6n/6=54/6

∙•❁ Your final answer is:

n=9

∙•❁I hope this helps!❁•∙

Harlamova29_29 [7]3 years ago

3 0

16-2n-5+8n=65 16-2n-5+8n=65
-2n+8n=65-16+5
6n=54
n=54/6
n=9

You might be interested in

Pls help me fast and give me the steps pls 1+7p-40=80

valentinak56 [21]

Answer:

Step-by-step explanation:

1+7p-40=80

-39+7p=80 Move constant to the right

7p=80+39 add the numbers

7p=119 divide both sides by 7

4 0

3 years ago

Read 2 more answers

Suppose that a family wants to start a college fund for their child. If you invest in an account that pays 5.5% and want the fun

vazorg [7]

The answer is 17040.34
Check the annuity due formula

7 0

3 years ago

Your friend claims that when a polynomial function has a leading coeffcient of 1 and the coefficients are all integers , every p

sammy [17]

Using the rational root theorem, it is found that your friend is correct.

<h3>What is the rational root theorem?</h3>

It is a theorem that states that for a polynomial with integer coefficients, with q being the factors of the leading coefficient and p being the factors of the constant, every possible rational root is the format $\frac{p}{q}$ .

In this problem:

The leading coefficient is 1, hence it's only factor is $q = 1$ , thus guaranteeing that every possible rational zero is an integer, which means that your friend is correct.

To learn more about the rational root theorem, you can take a look at brainly.com/question/10937559

8 0

2 years ago

I really need a answer ASAP

Elza [17]

Answer:

e and c

Step-by-step explanation:

4 0

3 years ago

If the endpoints of AB have the coordinates A(9, 8) and B(-1, -2), what is the midpoint of AB?

pickupchik [31]

The midpoint, if the endpoints are (x₁,y₁) and (x₂,y₂):
$(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

$(9,8) \\
x_1=9 \\ y_1=8 \\ \\
(-1,-2) \\
x_2=-1 \\ y_2=-2 \\ \\
\frac{x_1+x_2}{2}=\frac{9-1}{2}=\frac{8}{2}=4 \\
\frac{y_1+y_2}{2}=\frac{8-2}{2}=\frac{6}{2}=3$

The midpoint of AB is (4,3).

5 0

3 years ago

Read 2 more answers