<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
Answer:
the answer is 4
Step-by-step explanation:
because i did it on desmos that is a graphic calculator
Answer:
x = 41* & y = 90.
Step-by-step explanation:
Since we know that the figure is a right triangle, we can solve for y easily, as 90+y = 180
y = 90
to solve for x, we have 49+90+x, since the angle that makes up the left side is perpendicular to the triangle,
so 139+x = 180
x = 180-139
x = 41
