<span>A, B, and C are polynomials, where A = n, B = 2n + 6, and C = n2 – 1. What is AB – C in simplest form? We want (n)(2n+6) - (n^2-1). (Please note: n^2 is correct, while n2 is not.)
Multiplying out the first term: 2n^2 + 6n
Subtracting n^2-1: - (n^2 -1)
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n^2 + 6n + 1 (answer) </span>
Sent a picture of the solution to the problem (s).
Answer:
-11
Step-by-step explanation:
Answer: x = H(x) + 3
Step-by-step explanation: The inverse function is x expressed with H(x). There aren't always inverse functions but in this case you just put the fraction from the right hand side to the left hand side. After the divison you get what I wrote.
