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goldfiish [28.3K]
3 years ago
10

How do you factor this problem?

Mathematics
1 answer:
9966 [12]3 years ago
8 0
3m^3 -2m^2 + 4m + 2 

To factor the first problem you have to divide all by 4

The second one is m - <span>√16m +8

To factor the second problem you have to square root it all</span>
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Estimate the answer to the<br> calculation below<br> 21 X 385<br> 52
Andrei [34K]

Answer:

809,592

Step-by-step explanation:

21 x 38552= 809592

3 0
3 years ago
Given ao=-3 and an=2a,-1+1, find a4
sweet [91]

Answer:

8

Step-by-step explanation:

if you wrote out A(n) correctly than the answer is 8

8 0
3 years ago
The equation of the parabola is (y-1)^2 = 16(x+3)
Mandarinka [93]
We know that 

if  the y terms is squared so it opens left or right

Is a Horizontal Parabola, the equation is of the form
(y-k)²=4(p)(x-h)
vertex is (h,k)
and
p is distance from focus to vertex, also distance from vertex to directrix
if p>0, then it opens to the right and directrix is to the left of vertex
if p<0, then it opens to the left and directrix is to the right of vertex

so
(y-1)²=4(4)(x-(-3))
vertex is (-3,1)
4>0 so directrix is to left of vertex
left is in x direction
-3-4=-7
directrix is x=-7

the answer is
x=-7

see the attached figure

5 0
3 years ago
1=5 2=25 3=325 4=4325 6=?
Ipatiy [6.2K]

Answer:

6= 654325

:))))))))))

3 0
3 years ago
What are all values of x for which the series shown converges? ​
adoni [48]

Answer:

One convergence criteria that is useful here is that, if aₙ is the n-th term of this sequence, then we must have:

Iaₙ₊₁I < IaₙI

This means that the absolute value of the terms must decrease as n increases.

Then we must have:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}}

We can write this as:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}} = \frac{(x -2)^n}{(n + 1)*3^n} * \frac{(x - 2)}{3}

If we assume that n is a really big number, then:

n + 1 ≈ 1

And we can write:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2)^n}{(n)*3^n} * \frac{(x - 2)}{3}

Then we have the inequality

1 > (x - 2)/3

And remember that this must be in absolute value, then we will have that:

-1 < (x - 2)/3 < 1

-3 < x - 2 < 3

-3 + 2 < x < 3 + 2

-1 < x < 5

The first option looks like this, but it uses the symbols ≤≥, so it is not the same as this, then the correct option will be the second.

5 0
3 years ago
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