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Answer:
The margin of error for the 95% confidence interval used to estimate the population proportion is of 0.0209.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of .
The margin of error is of:
In a clinical test with 2161 subjects, 1214 showed improvement from the treatment.
This means that
95% confidence level
So , z is the value of Z that has a p-value of
, so
.
Margin of error:
The margin of error for the 95% confidence interval used to estimate the population proportion is of 0.0209.
The density of the gold sample is 19.3g/cm³
Let the mass of the gold sample be represented by m
m = 579 g
Let the volume of the gold sample be represented by V
V = 30 cm³
Let the density of the gold sample be represented by ρ
The formula for the density is:
The density of the gold sample is 19.3g/cm³
Learn more here: brainly.com/question/17780219