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Sati [7]
3 years ago
13

Due today HELP PLEASEEEEE!!!

Mathematics
1 answer:
Deffense [45]3 years ago
4 0

Answer:

Oiiiiio ka cha thik cha

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Three hundred and seven
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Examine the system of equations. −5x 5y = 40 4x 3y = 24 What is the solution? ( , ).
Elden [556K]

A system of equation is the set of equation in which the finite set of equation is present for which the common solution is sought.

The solution of the equation is (0,8)

<h3>What is system of equation?</h3>

A system of equation is the set of equation in which the finite set of equation is present for which the common solution is sought.

Given information-

The first equitation given in the problem is,

-5x+5y = 40

Divide both side of the above equation with 5 as,

\dfrac{(-5x+5y )}{5}= \dfrac{40}{5}\\-x+y=8\\y=8+x          .......1

Let the above equation as equitation 1.

The first equitation given in the problem is,

4x+ 3y = 24

Put the value of <em>y</em> form the equation 1 in the above equation as,

\begin{aligned}4x+ 3(x+8) &= 24\\4x+ 3x+24 &= 24\\4x+ 3x &= 24-24\\7x&=0\\x&=0\\\end

Put the value of <em>x</em> in the equation one as,

y=8+0\\y=8          

Thus the solution of the equation is (0,8)

Learn more about the system of equations here;

brainly.com/question/13729904

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Do you have a graph or a picture tagged along with the question

Step-by-step explanation:

Graph to solve?

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Aleka and Helene both opened savings accounts that earn 2.5% interest a year. Aleka puts $2,500 into her account. Helene put $1,
Angelina_Jolie [31]

Answer:

h(x)=1000(1.025)^x-200x.

Step-by-step explanation:

We are given function f for Aleka's amount

f(x)=2500(1.025)^x

And function for Helene's amount

g(x) = 1500(1.025)^x+200x.

Now, we need to find the difference of the functions h(x) = f(x)-g(x).

Subtracting f(x) and g(x), function, we get

h(x) =2500(1.025)^x-(1500(1.025)^x+200x)

Distributing minus sign over second parenthesis, we get

h(x) =2500(1.025)^x-1500(1.025)^x-200x

Subtracting 2500(1.025)^x-1500(1.025)^x, we get 1000.

Therefore, h(x)=1000(1.025)^x-200x.

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