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3 years ago

How would you put that in an equation?

Mathematics

1 answer:

Jet001 [13]3 years ago

6 0

Answer:

I don't see anything here attach first

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Differentiate Functions of Other Bases In Exercise, find the derivative of the function.

densk [106]

Answer:

The derivative of the function is:

$g'(x) = \frac{1}{1.6094x}$

Step-by-step explanation:

If we have a function in the following format:

$g(x) = \log_{a}{f(x)}$

This function has the following derivative

$g'(x) = \frac{f'(x)}{f(x)*\ln{a}}$

In this problem, we have that:

$g(x) = \log_{5}{x}$

So $f(x) = x, f'(x) = 1, a = 5$

The derivative is

$g'(x) = \frac{f'(x)}{f(x)*\ln{a}}$

$g'(x) = \frac{1}{x*\ln{5}}$

$g'(x) = \frac{1}{1.6094x}$

7 0

3 years ago

1.73629 rounded to the nearest thousand

shepuryov [24]

The answer will be 1.736

4 0

3 years ago

Heelelp meeeee pleaseeeeeeeeeeee

podryga [215]

Answer:

answer is 446

Step-by-step explanation:

7 0

3 years ago

If f(x) = 3^x + 10x and g(x) = 2x - 4 ding (f+g) (x)

liq [111]

$f(x)=3^x+10x;\ g(x)=2x-4\\\\(f+g)(x)=f(x)+g(x)=(3^x+10x)+(2x-4)=3^x+10x+2x-4\\\\\text{combine like terms}\\\\=3^x+(10x+2x)-4=\boxed{3^x+12x-4}$

4 0

3 years ago

Operations with radical expression

lord [1]

Hello from MrBillDoesMath!

Answer:

41 sqrt(3)

Discussion:

My first reaction to the problem was:

sqrt(27) = sqrt ( 3 * 9) = 3 sqrt(3) and

sqrt(48) = sqrt (3*16) = 4 sqrt(3).

So...

7 * sqrt(27) + 5 sqrt(48) =

7 * (3 sqrt(3)) + 5 * (4 sqrt(3)) =

21 sqrt(3) + 20 sqrt(3) =

41 sqrt(3)

Regards,

MrB

P.S. I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!

7 0

3 years ago