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lakkis [162]
3 years ago
10

Samual has an egg farm with a volume of 375 in.³ with the width of an ant farm is 2.5 inches and the length is 15 inches what is

the height of samuels ant farm
Mathematics
1 answer:
omeli [17]3 years ago
8 0

Answer:

The height is 10in

Step-by-step explanation:

If you need to calculate the volume, you need to know the formula. The formula is length x width x height. You have the length and width, so you need the height. 2.5in x 15in x 10in  = 375 in^3. You may ask why it is inches cubed instead of inches. It is inches cubed because you multiplied three inches together.

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A shop makes a profit of £2750 in March.
LiRa [457]

Answer:

15% increase

Step-by-step explanation:

2750... 10% of that is 275, add 275 to 2750 is 3025. 1% of 2750 is 27.50, you times that by 5, which is 137.50 and add that to 3025 giving you 3162.50, add the 10% with the 5% gives you 15%, that's the increase.

7 0
3 years ago
Can Someone Help Me Please. ?
asambeis [7]

Answer:

The answer is the third option from the top:

0, 0, 11, 15, 26, 32, 45, 46, 46, 46, 60, 71, 84, 88

7 0
2 years ago
You have been asked to design a rectangular box with a square base and an open top. The volume of the box must be 500cm3. Determ
babymother [125]

Answer:

x = 10 cm, y = 5 cm gives a minimum area of 300 cm^2.

Step-by-step explanation:

V= x^2y = 500

Surface area A = x^2 + 4xy.

From the first equation y = 500/x^2

So substituting for y in the equation for the surface area:

A = x^2 + 4x * 500/x^2

A = x^2 + 2000/x

Finding the derivative:

dA/dx = 2x - 2000x^-2

dA/dx = 2x - 2000/x^2

This = 0 for a minimum/maximum value of A, so

2x - 2000/x^2  = 0

2x^3 - 2000 = 0

x^3 = 2000/ 2 = 1000

x = 10

Second derivative is  2 + 4000/x^3

when x = 10  this is positive so x = 10 gives a minimum value of A.

So y =  500/x^2

= 500/100

= 5.

6 0
2 years ago
What is the distance from P to Q ?A. 7 unitsB. 5 unitsC. 1 unitD. 25 unitshow do I find the distance from P to Q?
Alex17521 [72]

to find the distance between 2 points we should apply the formula

d=\sqrt[]{(x_2-x_1)^2+(y_2-_{}y_1)^2_{}}

call point q as point 1 for reference in the formula and p as point 2

replace the coordinates in the formula

d=\sqrt[]{(3-(-1))^2+(-4-(-1))^2}

simplify the equation

\begin{gathered} d=\sqrt[]{(3+1)^2+(-4+1)^2} \\ d=\sqrt[]{4^2+(-3)^2} \\ d=\sqrt[]{16+9} \\ d=\sqrt[]{25} \\ d=5 \end{gathered}

the distance between the 2 points is 5 units

7 0
1 year ago
Hamburgers cost $2.50 and cheeseburgers cost $3.50 at a snack bar. Ben has sold no more than $30 worth of hamburgers and cheeseb
gregori [183]
Using the inequality
2.50x + 3.50y ≤ 30
substituting y with the number of cheeseburgers sold
2.5x + 3.5(4) ≤ 30
 x = 6.4
The maximum number of hamburgers he can sell is 6
5 0
3 years ago
Read 2 more answers
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