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deff fn [24]
4 years ago
5

Determine whether each relation is an equivalence relation. Justify your answer. If the relation is an equivalence relation, the

n describe the partition defined by the equivalence classes. (a) The domain is a group of people. Person x is related to person y under relation P if x and y have a common parent (i.e., x and y have the same biological mother or the same biological father or both). You can assume that there is at least one pair in the group, x and y, such that xPy. (b) The domain is a group of people. Person x is related to person y under relation M if x and y have the same biological mother. You can assume that there is at least one pair in the group, x and y, such that xMy. (c) The domain is a group of people. Person x is related to person y under relation S if x is currently the spouse of person y. You can assume that there is no polygamy and that there is at least one person who is married to another person in the group. (d) The domain is the set of all integers. xEy if x y is even. An integer z is even if z
Mathematics
1 answer:
Akimi4 [234]4 years ago
6 0

Answer:

ๆาหสไากใหทห

Step-by-step explanation:

วเมบหยทหยๆพืๆเงหิ วห

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SpyIntel [72]

the answer should $201.25

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Y=6*2x for x=-2 evaluate the function
atroni [7]

Answer:

Y = -24

Step-by-step explanation:

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6 0
3 years ago
what is (5.91 x 10^-3) - (8.7 x 10^10) written in a scientific notation? Please answer asap thank you :))
nata0808 [166]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the expression

\left(5.91\times \:10^{-3}\right)-\left(8.7\times \:10^{10}\right)

\mathrm{Remove\:parentheses}:\quad \left(a\right)=a

=5.91\times \:10^{-3}-8.7\times \:10^{10}

as

5.91\times \:10^{-3}

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

=5.91\times \frac{1}{10^3}

=\frac{5.91}{1000}

=0.00591

similarly

8.7\times \:10^{10}

Convert element to a decimal form

10^{10}=10000000000

so

=10000000000\times \:8.7

\mathrm{Multiply\:the\:numbers:}\:8.7\times \:10000000000=87000000000

=87000000000

Thus, the expression becomes

\left(5.91\times \:\:10^{-3}\right)-\left(8.7\times \:\:10^{10}\right)=5.91\times \:\:10^{-3}-8.7\times \:\:10^{10}

                                                =0.00591-87000000000

                                                =-86999999999.9941

Hence,

<em>converting -86999999999.9941 in a scientific notation</em>

In order to make our job easier we will remove the sign "-" from number -86999999999.9941 (we will write "-" at the final solution). So after this step we have:

<em>−86999999999.9941  ⟶  86999999999.9941</em>

<em></em>

In order to write number 86999999999.9941 in scientific notation, we need to move the decimal point from its current location (black dot) to the new position such as:

<em>8.6999999999.9941</em>

<em />

So, we need to move the decimal point 10 places to the right.

This means that the power of 10 will be positive 10.

Now we have that the

Number part = 8.69999999999941 and

Exponent part = 10

Thus, we conclude that:

−86999999999.9941 = − 8.69999999999941 × 10¹⁰

8 0
3 years ago
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