Answer:
Step-by-step explanation:
given,
radius of sphere = 3
volume of cone:
r is the radius of circular base
h is the height of the cone
here r = x and h = 3 + y
now, volume in term of x and y
Applying Pythagoras theorem
x² + y² = 3²
differentiating both side
for maxima 
y² + 2 y - 3 = 0
(y+3)(y-1)=0
y = 1,-3
y cannot be negative so, volume at y = 1
Hence, the largest cone which can be inscribed in the spheres of the radius 3 has volume
A tangent (here WZ in the question) to any circle (here O in the question) is a line segment that touches the circle at only one point (here B in the question) on circumference of circle, and the radius of the circle (here OB in the question) through this point is always perpendicular to that particular tangent.
In other words, Tangent (WZ) and Radius (OB) of any circle (O) always make a Right angle at point of intersection (B) on its circumference.
It means angle ∠OBZ would be a Right angle i.e. 90 degrees.
So, option B i.e. 90 degrees is the final answer.
Answer:
-4
Step-by-step explanation:
so t is greater than -5, and for negatives, you need to get nearer zero.
Answer:
use mathaway or algebra calculator they help alot
(z + 6) / 3 = 2z / 4
this is a proportion, so we cross multiply
(3)(2z) = 4(z + 6)
6z = 4z + 24
6z - 4z = 24
2z = 24
z = 24/2
z = 12 <==
