Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
If within the year 2014, the population p of the rabbits m months after January 2014 is modeled by the equation p = 0.05(m-1.5)(m-8.5) and the population reach 10,000 some time in February, to determine the time, given as months after January 1 2014, that the rabbit population reach ten thousand, we will substitute p = 10 into the modeled equation and get the value of m as shown;
![p = 0.05(m-1.5)(m-8.5)+10 \\substitute \ p = 10\\\\ 10 = 0.05(m-1.5)(m-8.5)+10\\\\10-10 = 0.05(m-1.5)(m-8.5)\\\\0 = 0.05(m-1.5)(m-8.5)\\\\0/0.05 = (m-1.5)(m-8.5)\\\\0 = (m-1.5)(m-8.5)\\ (m-1.5)(m-8.5) = 0\\ m-1.5 = 0 \ and \ m-8.5 = 0\\m = 1.5 \ and \ 8.5\\](https://tex.z-dn.net/?f=p%20%3D%200.05%28m-1.5%29%28m-8.5%29%2B10%20%5C%5Csubstitute%20%5C%20p%20%3D%2010%5C%5C%5C%5C%2010%20%3D%200.05%28m-1.5%29%28m-8.5%29%2B10%5C%5C%5C%5C10-10%20%3D%20%200.05%28m-1.5%29%28m-8.5%29%5C%5C%5C%5C0%20%3D%20%200.05%28m-1.5%29%28m-8.5%29%5C%5C%5C%5C0%2F0.05%20%3D%20%20%28m-1.5%29%28m-8.5%29%5C%5C%5C%5C0%20%3D%20%20%28m-1.5%29%28m-8.5%29%5C%5C%20%28m-1.5%29%28m-8.5%29%20%3D%200%5C%5C%20m-1.5%20%3D%200%20%5C%20and%20%5C%20m-8.5%20%3D%200%5C%5Cm%20%3D%201.5%20%5C%20and%20%5C%208.5%5C%5C)
Hence the population of the rabbit reach 10,000 after 1.5 months and 8.5 months
Answer:
![v = \pi \times {r}^{2} \times h](https://tex.z-dn.net/?f=v%20%3D%20%5Cpi%20%5Ctimes%20%7Br%7D%5E%7B2%7D%20%20%5Ctimes%20h)
Step-by-step explanation:
height=11km
diameter=10km
radius=diameter÷2
=10÷2
=5km
now,
volume=
![\pi \times {r}^{2} \times h \\ \frac{22}{7} \times {5}^{2} \times 11 \\ \frac{6050}{7} \\ 864.3 \: {km}^{3}](https://tex.z-dn.net/?f=%5Cpi%20%5Ctimes%20%20%7Br%7D%5E%7B2%7D%20%20%5Ctimes%20h%20%20%5C%5C%20%20%5Cfrac%7B22%7D%7B7%7D%20%20%5Ctimes%20%20%7B5%7D%5E%7B2%7D%20%20%5Ctimes%2011%20%20%5C%5C%20%5Cfrac%7B6050%7D%7B7%7D%20%20%5C%5C%20864.3%20%5C%3A%20%20%7Bkm%7D%5E%7B3%7D%20)
Answer:
-2.82842712475
Step-by-step explanation:
x^2+10+25=27
x^2+35=27
x^2+35-27=0
x^2+8=0
8=-x^2
SQR8=-x
-SQR8=x