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Mademuasel [1]
3 years ago
9

Find the balance after 8 years

Mathematics
1 answer:
AfilCa [17]3 years ago
7 0
Here’s the equation: 3000+0.03(3000)
But because it is 8 years:
3000+0.24(3000)
We can make it simpler:
1.24(3000)
3720
Your balance will be $3720
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People preferred berry blast by 780 compared to 220 who preferred Melon drink. Find the ratio
Airida [17]
Maybe ... divide the berry blast by the melon
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3 years ago
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Write the equation -4x^2+9y^2+32x+36y-64=0 in standard form. Please show me each step of the process!
IgorC [24]
Hey there, hope I can help!

-4x^2+9y^2+32x+36y-64=0

\mathrm{Add\:}64\mathrm{\:to\:both\:sides} \ \textgreater \  9y^2+32x+36y-4x^2=64

\mathrm{Factor\:out\:coefficient\:of\:square\:terms} \ \textgreater \  -4\left(x^2-8x\right)+9\left(y^2+4y\right)=64

\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4
-\left(x^2-8x\right)+\frac{9}{4}\left(y^2+4y\right)=16

\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}9
-\frac{1}{9}\left(x^2-8x\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}

\mathrm{Convert}\:x\:\mathrm{to\:square\:form}
-\frac{1}{9}\left(x^2-8x+16\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)

\mathrm{Convert\:to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)

\mathrm{Convert}\:y\:\mathrm{to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y+4\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)

\mathrm{Convert\:to\:square\:form}
-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)

\mathrm{Refine\:}\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right) \ \textgreater \  -\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=1

Refine\;once\;more\;-\frac{\left(x-4\right)^2}{9}+\frac{\left(y+2\right)^2}{4}=1

For me I used
\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}= 1
As\;\mathrm{it\;\:is\:the\:standard\:equation\:for\:an\:up-down\:facing\:hyperbola}

I know yours is an equation which is why I did not go any further because this is the standard form you are looking for. I would rewrite mine to get my hyperbola standard form. However the one I have provided is the form you need where mine would be.
\frac{\left(y-\left(-2\right)\right)^2}{2^2}-\frac{\left(x-4\right)^2}{3^2}=1

Hope this helps!
4 0
4 years ago
Will give first person to answer brainliest!! At a local baseball game, tickets cost $4 for adults and $2 for students. If there
S_A_V [24]

Answer:

let x adult and y student attended

x+y= 94

x=94-y

again

4x+2y = 294                               53 adults and 41 student attended

376-4y+2y =294                                           the  event

2y =82

y=41

substituting the value of y in

x+y =94

x= 94-41 = 53

Step-by-step explanation:

8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csf%2020%3D9x-7" id="TexFormula1" title="\sf 20=9x-7" alt="\sf 20=9x-7" align="absmiddle" cl
Temka [501]

Answer:

x=3.

Add-on:

hope this helped at all.

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What set of reflections and rotations would carry rectangle ABCD onto itself? Parallelogram formed by ordered pairs A at negativ
pickupchik [31]
Each of the 4 choices has been drawn step by step as follows:

the first transformation is drawn in light grey
the second transformation is drawn in dark grey
the third transformation is described as how it should be.


Choice I, picture I: 
Rotate 180°, reflect over the x-axis, reflect over the line y=x

the last transformation should be : reflect with respect to the y-axis


Choice II, picture II: 
Reflect over the x-axis, rotate 180°, reflect over the x-axis

the last transformation should be : reflect with respect to the y-axis



Choice III, picture III: 
Rotate 180°, reflect over the y-axis, reflect over the line y=x

the last transformation should be : reflect with respect to the x-axis



Choice IV, picture IV: 
Reflect over the y-axis, reflect over the x-axis, rotate 180°

the last transformation should be : rotate 180° CORRECT!



Answer:  Reflect over the y-axis, reflect over the x-axis, rotate 180°

6 0
3 years ago
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