Factor by using the difference of two cubes
1 answer:
Answer:
Step-by-step explanation:
a) a^3-64b^3
=(a)^3-(4b)^3
=(a-4b)(a^2+4ab+16b^2)
b) 3x^3-81y^3z^6
=3(x^3-27y^3z^6)
=3{(x)^3-(3yz^2)^3}
=3(x-3yz^2)(x^2+3xyz^2+9y^2z^4)
c)16a^3b^3-54c^3d^3
=2(8a^3b^3-27c^3d^3)
=2{(2ab)^3-(3cd)^3
=2(2ab-3cd)(4a^2b^2+6abcd+9c^2d^2)
hope u got!!
You might be interested in
5.7 is 5 7/10 and it cannot be simplified
Answer:
should be "d" though i haven't calculated it all exactly
Step-by-step explanation:
A : 85
B : 83
C : 82
D : 81
<h2>
We need more details for this question. We may not understand it because we could not see the data.</h2>
Here you go I hope this helps.
