Factor by using the difference of two cubes
1 answer:
Answer:
Step-by-step explanation:
a) a^3-64b^3
=(a)^3-(4b)^3
=(a-4b)(a^2+4ab+16b^2)
b) 3x^3-81y^3z^6
=3(x^3-27y^3z^6)
=3{(x)^3-(3yz^2)^3}
=3(x-3yz^2)(x^2+3xyz^2+9y^2z^4)
c)16a^3b^3-54c^3d^3
=2(8a^3b^3-27c^3d^3)
=2{(2ab)^3-(3cd)^3
=2(2ab-3cd)(4a^2b^2+6abcd+9c^2d^2)
hope u got!!
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