3 years ago

How do you divide a negative number and a positive number?

Mathematics

1 answer:

Airida [17]3 years ago

8 0

When dividing a negative and a postive number, the answer will always be negative.

ex)
-4/2=-2

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Is 124 a whole number

Svet_ta [14]

Answer:

yes, fractions are like 1/2 or 3/6 but a whole number is not a part or a fraction such as 124.

Step-by-step explanation:

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3 years ago

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What is the answer ????

zlopas [31]

I think its c hope this helps sorry if it dont

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3 years ago

The standard form of the number represented by the Roman numeral MXCIV is

Assoli18 [71]

Answer:

1094

Step-by-step explanation:

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2 years ago

Factor the polynomial function over the complex numbers. f(x)=x^4-x^3-2x−4 Enter your answer in the box. f(x) = The answer is: (

Vladimir79 [104]

Answer:

Factors: $(x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0$

Step-by-step explanation:

We are given a polynomial:

$f(x)=x^4-x^3-2x-4$

We have to factor the given polynomial into its complex factors.

The factorization can be done as follows:

$f(x)=x^4-x^3-2x-4 = 0\\x^4-x^3-2x-4 = 0\\x^4-4-x^3-2x=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^4-4)-(x^3+2x) = 0\\(x^2+2)(x^2-2)-x(x^2+2) = 0\\(x^2+2)(x^2-2-x) = 0\\(x^2+2)(x^2-x-2) = 0\\(x^2+2)(x^2-2x-+x-2) = 0\\(x^2+2)((x(x-2)+1(x-2))=0\\(x^2+2)(x+1)(x-2)=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^2-(\sqrt{-2})^2)(x+1)(x-2)=0\\(x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0$

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2 years ago

One angle measure in an acute triangle is 38°. What could the measure of one of the other angles be?

Oksi-84 [34.3K]

If is an acute triangle, all the angles should be acute angles.
180-38=142°
142-69=73°
So your answer is 69°, lovely~

3 0

3 years ago

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