Dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
As given in the question,
P(x) be the given polynomial
Dividing P(x) by divisor (x-6) we get,
Quotient = Q(x)
Remainder = 5
Relation between polynomial, divisor, quotient and remainder is given by :
P(x) = Q(x)(x-6) + 5 __(1)
Given Q(-6) = 3
Put x =-6 we get,
P(-6) = Q(-6)(-6-6) +5
⇒ P(-6) = 3(-12) +5
⇒ P(-6) =-36 +5
⇒ P(-6) = -31
Now x =6 in (1),
P(6) = Q(6)(6-6) +5
⇒ P(6) = Q(6)(0) +5
⇒ P(6) = 5
Therefore, dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
The complete question is:
Dividing the polynomial P(x) by x - 6 yields a quotient Q(x) and a remainder of 5. If Q(-6) = 3, find P(-6) and P(6).
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No because 4 square equals 2 square and since 3 isn't a perfect number, it would be 2 square times 3 square, which equals 6 square.
Answer:
Answer is "No real Solution"
Answer:
I am 76 years old.
Step-by-step explanation:
If my age is x years then:
200 - 2x = 48
-2x = - 152
x = 76.
