To solve the problem you must find the area of every square. For F one of the squares has a side length of 3 and because this is a square the other sides are also 3. To find the area we multiply two of the sides so 3 times 3 is 9
You do this with both the other squares
3*3=9
4*4=16
The area of the large square is given as 25
So 9+16=25 which means this is not the correct answer
H.
9*9=81
Given as 144
The area of the large square is 21*21 which is 441
144+81= 225
So because the two small squares DO NOT equal the area of the large square this is the correct answer.
Find the volumes of each separate rectangular prism, (top) 9 x 4 x 12 = 432 cubic meters, (bottom) 10x2x2 = 40 cubic meters, and then add them together to get the overall volume, 40+432 = 472 cubic meters. the strategy is using length times width times height, LxWxH.
Answer:
Coordinates of Vertices of triangle ABC are A (-4,3) , B(4,4) and C(1,1).
As, DO is Dilation of Δ ABC by Scale factor of
.
Vertices of A' B'C' are

So, Image Δ A'B'C' will be smaller than the Pre image Δ ABC.
The two triangles will be congruent.
AO is Dilated by a factor of half , so A'O' will be half of AO.
So, correct Statements are
1. AB is parallel to A'B'.
2.DO,1/2(x, y) =
The distance from A' to the origin is half the distance from A to the origin.
The average travel time is simply the mean travel time between the given points
- The average time that it takes for the car to travel the first 0.25m is 2.23s.
- The average time to travel just between 0.25m and 0.50m is 0.9s.
- Given the time taken to travel the second 0.25 m section, the velocity would be 0.28m/s.
<u>(a) The average time to travel the first 0.25m</u>
The time travel in the first 0.25m are: 2.24s, 2.21s and 2.23s.
So, the average time to travel is:



<u>(b) The average time to travel just between 0.25m and 0.50m</u>
The time travel in the 0.50m are: 3.16s, 3.08s and 3.15s.
So, the average time to travel this distance is:



The average time to travel between both distance is the difference between the average time of each distance.
So, we have:


<u>(c) The velocity in the second 0.25m section</u>
The distance and time are:


So, the velocity is:

This gives


Read more about distance, velocity and time at:
brainly.com/question/4931057