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timurjin [86]
3 years ago
14

mark read 203 pages.Laney read 100 more pages than Mark. Gavin read 10 fewer pages than Laney.How many pages did Gavin read?

Mathematics
1 answer:
Alex3 years ago
6 0
293 ages he read 293 pages
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A box contains 10 tags, numbered 1 through 10, with a different number on each tag. A second box contains 8 tags, numbered 20 th
blagie [28]

Answer:

E) 29.0

Step-by-step explanation:

The value of the sum is obtained from 2 independent experiments: the value of the number of the first box X₁ and the value of the number of the second box X₂.

The expected value of a draw is the average of all its values, so E(X₁) = (1+2+3+4+5+6+7+8+9+10)/10 = 5.5 and E(X₂) = (20+21+22+23+24+25+26+27)/8 = 23.5

Hence, E(X₁+X₂) = E(X₁)+E(X₂) = 5.5+23.5=29

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3 years ago
A song by me
Deffense [45]

Answer:

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6 0
3 years ago
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How to simplify bracket five x squared plus three x minus two bracket plus bracket three x minus two x plus five bracket
Scilla [17]

Answer:

5x^2 + 4x + 3.

Step-by-step explanation:

While I'm a little confused on what is closed and open parenthesis/brackets, I think I understand what you mean. In (5x^2+3x-2)+(3x-2x+5), the brackets can simply be removed as there is no multiplication between them. This means we get 5x^2 + 3x - 2 + 3x - 2x + 5. Combining like variables, we get 5x^2 + 4x + 3.

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3 years ago
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The probability that a customer's order is not shipped on time is 0.06. A particular customer places three orders, and the order
charle [14.2K]

Answer:

a) There is a 83.06% probability that all orders are shipped on time.

b) There is a 15.90% probability that exactly one order is not shipped ontime.

c) The probability of at least two orders being late is 1.02% + 0.02% = 1.04%.

Step-by-step explanation:

Probability:

What you want to happen is the desired outcome.

Everything that can happen iis the total outcomes.

The probability is the division of the number of possible outcomes by the number of total outcomes.

In our problem, there is:

-A 6% probability that a customer's order is not shipped on time.

-A 94% probability that a customer's order is shipped on time.

We have these following orders:

O1 - O2 - O3.

(a) What is the probability that all are shipped on time?

The probabilities that each order is shipped on time are O1 = 0.94, O2 = 0.94 and O3 = 0.94. So:

P = (0.94)^{3} = 0.8306

There is a 83.06% probability that all orders are shipped on time.

(b) What is the probability that exactly one is not shipped ontime?

The order's can be permutated. What this means? It means that we can have O1 late and O2,03 on time, O2 late and O1,O3 on time and O3 late and O1, O2 on time. We have a permutation of 3 elements(the orders) with 2 and 1 repetitions(2 on time and one late).

The probability that an order is late is:

P = (0.94)^{2}(0.06) = 0.053 for each permutation

Considering the permutations:

P = 0.053*p^{3}_{2,1} = 0.053\frac{3!}{2!*1!} = 0.053*3 = 0.1590

There is a 15.90% probability that exactly one order is not shipped ontime.

(c) What is the probability that two or more orders are not shipped on time?

P = P1 + P2, where P1 is the probability that two orders are late and P3 is the probability that all three orders are late.

P1

Considering the permutations, the probability that two orders are late is:

P_{1} = p^{3}_{2,1}*(0.94)*(0.06)^{2} = 3*(0.94)*(0.06)^{2} = 0.0102

There is a 1.02% probability that two orders are late

P2

P_{2} = (0.06)^3 = 0.0002

There is a 0.02% probability that all three orders are late.

The probability of at least two orders being late is 1.02% + 0.02% = 1.04%.

5 0
3 years ago
Please solve ASAP!<br> (⁴√9)(√9) ÷ ⁴√9⁵
-Dominant- [34]

Answer:

(\sqrt[4]{9})(\sqrt{9})\div \sqrt[4]{9^5}=\frac{\textbf{1}}{\sqrt{\textbf{9}}}

Step-by-step explanation:

Given expression is

(\sqrt[4]{9})(\sqrt{9})\div \sqrt[4]{9^5}

The above expression can be written as

\frac{(9)^{\tfrac{1}{4}}(9^{\tfrac{1}{2}})}{(9^5)^{\tfrac{1}{4}}}

=\frac{9^{\tfrac{1+2}{4}}}{9^{\tfrac{5}{4}}}    (by using the formula a^m\times a^n=a^{m+n})

=9^{\tfrac{3}{4}}\times 9^{\tfrac{-5}{4}}   (by using the formulae {(a^m)}^n=a^{mn} and \frac{a^m}{a^n}=a^{m-n})

=9^{\tfrac{-2}{4}}

=9^{\tfrac{-1}{2}}

=\frac{1}{9^{\tfrac{1}{2}}}

(\sqrt[4]{9})(\sqrt{9})\div \sqrt[4]{9^5}=\frac{\textbf{1}}{\sqrt{\textbf{9}}}

4 0
3 years ago
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