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podryga [215]
3 years ago
11

(-2x + 10)- (-6+5y+12) +(x + 8y - 16

Mathematics
1 answer:
Mamont248 [21]3 years ago
4 0
Answer:
-x - 12 + 3y

Step by step explanation:

-2x + 10 - (6 + 5y) + x + 8y - 16

-2x + 10 - 6 - 5y + x + 8y -16

-x - 12 + 3y
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It is the second one
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You and a friend are playing a best-of-three series (first to win 2 games wins the series). You are a stronger player and have a
mariarad [96]

Answer and Step-by-step explanation:

Given that probability of you winning each game = 0.68

And probability of you winning next game = 0.81

Your friend's chance of winning/you losing would be = 1-0.68= 0.32

also his chance of winning next game = 0.73

To find probability that you would win the series given that you need to win two games to win the series

= probability that you win first game and second game+ probability that you win first game, lose second game and win third game + probability that you lose first game, win second game and win third game

= 0.68*0.81+0.68*0.32*0.68+0.32*0.68*0.81

=0.8750

Therefore probability that you would win the series = 0.8750

Note: here we found the probability of winning by adding(or) up the three possible combinations that would result in a win

6 0
3 years ago
Which relationship describes angles 1 and 2?
11Alexandr11 [23.1K]

the relationship between the two angles is that they are supplementary angles because together they create a line that is 180 degrees. I might be wrong so please don't get mad if I am. I am 90 percent sure this is the answer though

7 0
4 years ago
The given two-parameter family is a solution of the indicated differential equation on the interval
mr_godi [17]

Answer:

I do 1 option for you as an example, you need to check the leftover by yourself.

Step-by-step explanation:

for d) y(0) = 0 and y'(pi) =0

y(0) = C_1e^0cos(0)+ C_2 e^0 sin(0) = 0 \longrightarrow C_1 = 0

y(x) ' = C_1e^x cos(x) - C_1e^x sin (x) + C_2e^x sin(x) + C_2e^x cos(x)

y(\pi)'=C_1e^\pi cos(\pi)- C_1e^\pi sin(\pi)+ C_2e^\pi sin(\pi) + C_2e^\pi cos (\pi)

Replace C_1 = 0 we have

y'(\pi) = -C_2e^\pi = 0

if and only if C_2 =0

Hence the given solution does not work.

then, d is NOT the correct answer.

3 0
3 years ago
3. A quadratic polynomial whose<br>product and the sum of<br>zéroes are -12 and 1​
muminat

Answer:

the equation is : x²-x-12

Step-by-step explanation:

the quadratic equation is in the form of : y=ax²+bx+c

the product of the zeros is -12 and the sum is 1

b  = - 1

c=-12 (product)

y=x²-x-12

check : factorize first (x+3)(x-4)=0

either x+3=0 then x=-3

or x-4=0 then x=4

-3*4=-12

-3+4=1

the equation is : x²-x-12

3 0
4 years ago
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