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3 years ago

Graph a line through the point (-3, 2) with a slope of -2/5 .

Mathematics

1 answer:

alexira [117]3 years ago

7 0

Answer:

y = $-\frac{2}{5} x$ $-\frac{16}{5}$

Some of the points on the graph are: (0,-3.2),(-8,0),(2,-4), and (-3,-2)

Step-by-step explanation:

https://www.d esmos.com/calculator/jx7d3ews7b

Brainly has been acting up. It won't let us paste links.

So when copying and pasting the link above, remove the space between d and e to get the graph.

Hope that helps!

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Lubov Fominskaja [6]

Answer:

x=5

Step-by-step explanation:

(8x-8)3/2=64

(24x-8)/2=64 -You are distributing the three

12x-4=64 -You divide the whole thing by two

12x=60 -You subtract the four from both sides

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Hope this helps!

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3 years ago

The roots of the equation x2 - 14x + 48 = 0) are

MrRissso [65]

Answer:

${x}^{2} - 14x + 48 = 0 \\ {x}^{2} - 6x -8 x + 48 = 0 \\ x(x - 6) - 8(x - 6) = 0 \\ (x - 6)(x - 8) = 0 \\ \boxed{ x = 6\: and \: 8}$

4) 6 and 8 is the right answer.

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2 years ago

Find the area each sector. Do Not round. Part 1. NO LINKS!!

sladkih [1.3K]

Answer:

$\textsf{Area of a sector (angle in degrees)}=\dfrac{\theta}{360 \textdegree}\pi r^2$

$\textsf{Area of a sector (angle in radians)}=\dfrac12r^2\theta$

17) Given:

$\theta$ = 240°
r = 16 ft

$\textsf{Area of a sector}=\dfrac{240}{360}\pi \cdot 16^2=\dfrac{512}{3}\pi \textsf{ ft}^2$

19) Given:

$\theta=\dfrac{3 \pi}{2}$
r = 14 cm

$\textsf{Area of a sector}=\dfrac12\cdot14^2 \cdot \dfrac{3\pi}{2}=147 \pi \textsf{ cm}^2$

21) Given:

$\theta=\dfrac{ \pi}{2}$
r = 10 mi

$\textsf{Area of a sector}=\dfrac12\cdot10^2 \cdot \dfrac{\pi}{2}=25 \pi \textsf{ mi}^2$

23) Given:

$\theta$ = 60°
r = 7 km

$\textsf{Area of a sector}=\dfrac{60}{360}\pi \cdot 7^2=\dfrac{49}{6}\pi \textsf{ km}^2$

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2 years ago