Question

When an object is dropped from a building​ (height 16501650 ​feet), the​ object's height,​ h, in​ feet, from the ground at​ time, t, in​ seconds, after being dropped can be determined by h equals Upper P (t )equals negative 16 t squared plus 1650.h=P(t)=−16t2+1650. Find the distance an object is from the ground 33 seconds after being dropped.

Answer 1

Answer:

1515 feet

Step-by-step explanation:

The height, h (in feet ) of the object from the ground after a given time (t) in seconds is given as:

h=P(t)=−16t²+1650

To determine the height after 3 seconds of an object being dropped, i.e. at t=3

P(t)=−16t²+1650

P(t)=−16(3)²+1650

=-16(9)+1659

=-144+1659

P(t)=1515 feet

The height of the object from the ground after 3 seconds is 1515 feet