Answer:
the 2nd
Step-by-step explanation:
F = 15%
v = 5%
0.15f + 0.05v = 0.14*10
15f + 5v = 140
3f + v = 28
f + v = 10 (total volume)
---------- Subtract
2f = 18
f = 9 liters of 15%
v = 1 liter of 5%
Answer:
Yes
Step-by-step explanation:
First, suppose that nothing has changed, and possibility p is still 0.56. It's our null hypothesis. Now, we've got Bernoulli distribution, but 30 is big enough to consider Gaussian distribution instead.
It has mean μ= np = 30×0.56=16.8
standard deviation s = √npq
sqrt(30×0.56×(1-0.56)) = 2.71
So 21 is (21-16.8)/2.71 = 1.5494 standard deviations above the mean. So the level increased with a ˜ 0.005 level of significance, and there is sufficient evidence.
1+38*225(12/77)
1+38*225*6.41
1*8550*6.41
1+54,805.5
54,806.5
Use pemdas to solve it
7 to 8 i think............................
