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Genrish500 [490]
3 years ago
13

On his fishing trip Justin rides on hist 12 km south. The fish aren't biting so he changes location and goes 4 km west. What is

Justin's displacement?
Mathematics
1 answer:
Sati [7]3 years ago
6 0

Answer:

Justin's displacement is 12.65 km.

Step-by-step explanation:

Since Justin rides 12 km south, then 4 km west, his displacement can be determined by applying Pythagoras theorem to the sketch of his journey. Let his displacement be represented by s,

/Hyp/^{2} = /Adj1/^{2} + /Adj2/^{2}

s^{2} = /4/^{2} + /12/^{2}

   = 16 + 144

s^{2}  = 160

⇒ s = \sqrt{160}

      = 12.6491

s ≅ 12.65 km

Justin's displacement is 12.65 km.

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(1) Let {v1,v2,v3} be a set of vectors in Rn . If u is Span {v1,v2,v3}, show that 3u is in Span {v1,v2,v3}.
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(1)

Multiplying by 3 both sides of the equality you get that

3u = 3c_1v_1+3c_2v_2+3c_3v_3

3u  is in the Span of the vectors \{v_1,v_2,v_3\}.

(2)

That's not true, consider the following counter example.

v_1 = (0,0,0,1)\\v_2 = (0,0,1,0)\\v_3 = (0,1,0,0)\\v_4 = (1,0,0,0)\\u = (0,1,1,1)

u is a linear combination of v_1,v_2,v_3 but is NOT a linear combination of v_1,v_2,v_3,v_4.

Step-by-step explanation:

(1)

As the hint indicates, you know that

u = c_1 v_1 + c_2v_2+c_3v_3

Then, if you multiply both sides of the equality by 3, you get that

3u = 3c_1v_1+3c_2v_2+3c_3v_3

And that's it. 3u  is in the Span of the vectors \{v_1,v_2,v_3\}

(2)

That's not true, consider the following counter example.

v_1 = (0,0,0,1)\\v_2 = (0,0,1,0)\\v_3 = (0,1,0,0)\\v_4 = (1,0,0,0)\\u = (0,1,1,1)

u is a linear combination of v_1,v_2,v_3 but is NOT a linear combination of v_1,v_2,v_3,v_4.

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