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Inga [223]
3 years ago
8

Please help me solve this!!!!!

Mathematics
1 answer:
gulaghasi [49]3 years ago
8 0

Answer

Burger meal = $8 and Hot dog meal = $6

Step-by-step explanation:

Let's use "x" to represent burger meals and "y" to represent hot dog meals.

Garcia family:

3x + 4y = $48

Baker family:

6x + 2y = $60

We have to first compare both families' and then eliminate one of our common variables, either the "x" or "y".

3x + 4y = $48

6x + 2y = $60

Let's eliminate "x". To do this we can multiply "3x" by "-2" to get "-6x". This will cancel out "6x":

-2 (3x + 4y = $48) ...our new equation would be....

-6x - 8y = -$96

Now to add our two families' equations together...

-6x - 8y = -$96

+

6x + 2y = $60

=

- 6y = -$36

Divide both sides by "-6" to get "y" by itself.

y = $6

We now know the value of "y" <em>or </em>one hot dog meal. Next, we want to solve for "x", our variable for the hamburger meal... We will plug in our y value to help us...

3x + 4(6) = $48

3x + 24 = $48

We want to get our x by itself. First, we can subtract 24 from each side.

3x = $24

Then we will divided both sides by 3 to get x alone.

x = $8

To check our work we can plug in our values for both "x" and "y" to see if they add up to $48 and $60:

3(8) + 4(6) = $48

24 + 24 = $48

and...

6(8) + 2(6) = $60

48 + 12 = $60

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First put the equation into standard form by isolating y:
y=-0.5x+5
To convert x to have no coefficients, the coefficient is really 1, so multiplying everything by -2 and you get
-2y=x-10
8 0
3 years ago
Thanks to whoever decides to help :)
Ostrovityanka [42]

Answer:

(-4,5) if it is rotated 90 degree counterclockwise

3 0
3 years ago
Read 2 more answers
Is y=x^2 a proportional relationship?
TiliK225 [7]

Answer:

is y=x^2 a proportional relationship?

{ \sf{yes. \: constant \: of \: proportionality = 1}}

is y=2+x a proportional relationship?

{ \sf{no. \: unless \: y \: is \: proportinal \: to \: (2 + x)}}

is y=2/x a proportional relationship?

{ \sf{yes. \: where \: proportianality \: constant \: is \: 2}}

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6 0
3 years ago
In a survey of 300 college graduates, 53% reported that they entered a profession closely related to their college major. If 9 o
ExtremeBDS [4]

Answer:

0.1348 = 13.48% probability that 3 of them entered a profession closely related to their college major.

Step-by-step explanation:

For each graduate, there are only two possible outcomes. Either they entered a profession closely related to their college major, or they did not. The probability of a graduate entering a profession closely related to their college major is independent of other graduates. This, coupled with the fact that they are chosen with replacement, means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

53% reported that they entered a profession closely related to their college major.

This means that p = 0.53

9 of those survey subjects are randomly selected

This means that n = 9

What is the probability that 3 of them entered a profession closely related to their college major?

This is P(X = 3).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{9,3}.(0.53)^{3}.(0.47)^{6} = 0.1348

0.1348 = 13.48% probability that 3 of them entered a profession closely related to their college major.

6 0
3 years ago
Quick!! I need help with this question!
d1i1m1o1n [39]

1. 60 / 1/8 * 3/4

2. 3/4 * 15

3. 7/8 / 3/4

3 0
3 years ago
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