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Karo-lina-s [1.5K]

3 years ago

9

Help i need clean and clear answers thanks

1 answer:

Phoenix [80]3 years ago

8 0

-6x+8 I thinkz thtats the correct answer

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4x-3y=2<br> 3x=5y=16<br> solve using substitution method

vodomira [7]

$\left\{\begin{array}{ccc}4x-3y=2&|\text{add 3y to both sides}\\3x+5y=16\end{array}\right\\\left\{\begin{array}{ccc}4x=3y+2&|\text{divide both sides by 4}\\3x+5y=16\end{array}\right\\\left\{\begin{array}{ccc}x=0.75y+0.5&(*)\\3x+5y=16\end{array}\right\\\\\text{substitute}\ (*)\ \text{to the second equation}\\\\3(0.75y+0.5)+5y=16\qquad\text{use distributive property}\\\\(3)(0.75x)+(3)(0.5)+5y=16\\\\2.25y+1.5+5y=16\qquad\text{subtract 1.5 from both sides}\\\\7.25y=14.5\qquad\text{divide both sides by 7.25}$

$\boxed{y=2}\\\\\text{substitute the value of y to}\ (*):\\\\x=0.75(2)+0.5\\\\x=1.5+0.5\\\\\boxed{x=2}\\\\Answer:\ x=2\ and\ y=2\to(2,\ 2)$

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What is the probability that a red or green marble will be selected from a bag containing 9 red marbles, 6 blue marbles, 7 green

lara31 [8.8K]

Answer: $\bold{\dfrac{16}{33} = 48\%}$

<u>Step-by-step explanation:</u>

Red or Green

$=\dfrac{red}{total}+\dfrac{green}{total}$

$=\dfrac{9}{33}+\dfrac{7}{33}$

$=\dfrac{16}{33}$

≈ 48%

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