The percentage of the offspring that will have atatched earlobes as the dominant trait, is: 50%.
What is a Dominant Trait?
A dominant trait surpresses a recessive trait, and expresses itself. The allele of a dominant trait is usally denoted using capital letters.
Given the following traits:
A - attached earlobes (dominant allele)
a - unattached earlobes (recessive allele)
A cross between Aa and aa is shown in the image attached below.
The offspring having attached earlobes = 2 Aa = 50%.
50% of the osspring will have attached earlobes.
Learn more about dominant trait on:
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Are you asking what they should do because of the profit ?
Answer:
r = ∛(3V/4π)
Step-by-step explanation:
The formula for the volume of a sphere is V = (4/3)πr³.
We want to solve this first for r³ and then for r.
Multiplying both sides of V = (4/3)πr³ by 3 yields an equation without fractions: 3V = 4πr³.
Dividing both sides of this equation by 4π isolates r³:
3V
r³ = -------
4π
To find r, take the cube root of both sides of
3V
r³ = -------
4π
obtaining r = ∛(3V/4π)
Answer:
130.826 kilojoules
Step-by-step explanation:
The Work required to pump water = pgV
Where, p = density of water = 1000 kg/m³
g = acceleration due to gravity = 9.81ms-¹
V = volume of water
Since, radius r = 5 ft and height h = 9ft
Volume of water in the cylindrical tank = (2/3)πr²h
V = (2/3)π *5²*9 = 471.24 ft³ = 471.24 * 0.0283m³ = 13.336m³
Work required = 1000*9.81*13.336
W = 130.826 KJ
Therefore, the work required to pump water 2/3 of the volume of the cylindrical tank = 130.826 kilojoules.
11 = 0.125
12 = 0.16
13 = 0.083
14 = 0.1
