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3 years ago

Kylie and her two sisters each have 1/4 cup of chopped pineapple how much pineapple do they have in all

Mathematics

2 answers:

lbvjy [14]3 years ago

5 0

They all together have 1/8 of a cup

DochEvi [55]3 years ago

3 0

3/4 in all
Hope it helps

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2x - 2y = 22 find the value of y when x equals 2

Vika [28.1K]

Answer:

y=-9

Step-by-step explanation:

If x equals 2, then we can substitute that into the equation, resulting in the equation 2*2-2y=22

We can solve for multiplication first:

4-2y=22

Then we can subtract four on both sides, canceling out the four on the left side:

-2y=18

Now to isolate y, we divide both sides by -2, resulting in the solution:

y=-9

Hope this helps!

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2 years ago

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In an A-frame house, the two congruent sides each form a 76° angle with the ground. What is the angle formed at the peak by the

Doss [256]

28 degrees is the answer , 76+76= 152, 180-152+ 28

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2 years ago

A large botanical garden has a total of 500 trees, bushes, and cacti. Pie chart with the following pieces: blue section titled t

Tanzania [10]

There are 190 trees.

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2 years ago

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What is the answer? please

liubo4ka [24]

Answer:

2 $x^{2}$ -2 $x$ +3

Step-by-step explanation:

Take both polynomials out of parenthesis, then combine like terms.

5 $x^{2}$ -3 $x^{2}$ =2 $x^{2}$

6 $x$ -8 $x$ = $-2x$

$-7+10=3$

5 0

2 years ago

B) Consider the weighted voting system (q: 8,4,2,1). Find the Banzhaf power distribution of this weighted voting systwm when q=1

pashok25 [27]

Answer:

Given : (q: 8,4,2,1)

q = 15

List all coalitions ( 2 pair)

$(P_1,P_2)=\text{Total weight }=8+4=12 \\(P_1,P_3)\text{Total weight }=8+2=10 \\(P_1,P_4)\text{Total weight }=8+1=9 \\(P_2,P_3)\text{Total weight }=4+2=6 \\(P_2,P_4)\text{Total weight }=4+1=5 \\(P_3,P_4)\text{Total weight }=2+1 = 3$

Those whose total weight is equal to q or more than q will go further in the list of winning coalitions

Since No pair's total weight is equal to q or more than q . So, we will not consider then further

Coalitions ( 3 pair or more)

$(P_1,P_2,P_3)=\text{Total weight }=8+4+2=14 \\(P_1,P_2,P_4)\text{Total weight }=8+4+1=13 \\(P_1,P_3,P_4)\text{Total weight }=8+2+1=11 \\(P_2,P_3,P_4)\text{Total weight }=4+2+1=7 \\(P_1,P_2,P_3,P_4)\text{Total weight }=8+4+2+1=15$

Those whose total weight is equal to q or more than q will go further in the list of winning coalitions

winning coalitions:

$(P_1,P_2,P_3,P_4)$

If Player 1 leaves

So, total weight will be 4+2+1 = 7

So, Player 1 is critical

If Player 2 leaves

So, total weight will be 8+2+1 = 11

So, Player 2 is critical

If Player 3 leaves

So, total weight will be 8+4+1 = 13

So, Player 3 is critical

If Player 4 leaves

So, total weight will be 8+4+2 = 14

So, Player 4 is critical

Player Times critical Banzhaf power index

1 1 $\frac{1}{4} \times 100 = 25\%$

2 1 $\frac{1}{4} \times 100 = 25\%$

3 1 $\frac{1}{4} \times 100 = 25\%$

4 1 $\frac{1}{4} \times 100 = 25\%$

Sum = 4

7 0

2 years ago