Answer:
A) 200 in²
Step-by-step explanation:
Height of the front rectangle
sqrt(6² + 6²)
6sqrt(2)
3 rectangles + 2 triangles
(6×8) + (6×8) + (8×6sqrt(2)) + (2×½×6×6)
132 + 48sqrt(2)
199.8822509939
I can't solve it but you can enter the equation into www.quickmath.com and it will give you the answer. Hope it helps.
14r+20<14r+16 or 8−10r>15−9r
14r+20<14r+16
14r+20−14r<14r+16−14r(Subtract 14r from both sides)
20<16
20−20<16−20(Subtract 20 from both sides)
0<−4
8−10r>15−9r
−10r+8>−9r+15(Simplify both sides of the inequality)
−10r+8+9r>−9r+15+9r(Add 9r to both sides)
−r+8>15
−r+8−8>15−8(Subtract 8 from both sides)
−r>7
−r/−1 > 7/−1(Divide both sides by -1)
r<−7
Ur answer is:
r < - 7 OR 0 < - 4
