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Stels [109]
3 years ago
13

How do you write 0.8959 as a percentage?

Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
5 0

Answer:

Step-by-step explanation:

89.59%

Hope that helps!

levacccp [35]3 years ago
5 0

Answer:

0.1%

Step-by-step explanation:

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2. Tyson multiplies 75 by 1.15. Which number might Tyson be trying to find? |A 115%of 75||| B 15% of 75||| C 11.5% of 75||| D 1.
Yanka [14]

Answer:

115% of 75 is equivalent to 75 by 1.15 = 8.625 , This two are equivalent

Step-by-step explanation:

Given as :

Tyson multiplies 75 by 1.15

I .e 75 × 1.15 = 86.25

Now A ) 115% of 75 = \frac{115}{100} × 75 = 86.25

B) 15% of 75 = \frac{15}{100}  × 75 = 11.25

C) 11.5% of 75 = \frac{11.5}{100} × 75 = 8.625

D) 1.15% of 75 = \frac{1.15}{100} × 75 = 0.8625

∵ 115% of 75 is equivalent to 75 by 1.15   ,  so Tyson try to find the option A

Answer

7 0
3 years ago
Which equation represents the graph of the linear function?
Flura [38]
Since the line is going from the top left to the bottom right, the slope is negative so A and B are possible answers.

the line crosses the y axis at -1
B is the option that ends with -1

therefore your answer is B. y = -2x - 1
5 0
3 years ago
How many different arrangements can be made with the letters in the word POWER?
Burka [1]
120 different arrangements
6 0
3 years ago
The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width
blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given  perimeter

perimeter of rectangle = 2 ( length +  width )

=> 30.8 km = 2 ( x + y )  

=>x + y = \frac{30.8}{2}

=> y = 15.4 – x             ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,  

=> length^2 + width^2 = diagonal^2

=> x^2 + y^2 = 11^2

=> x^2 + y^2 = 121

On substituting value of y from (1) in above equation we get

=> x^2 + (15.4-x)^2 = 121

=>x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x   = 121

=> 2x^2-30.8x + 237.16 -121  = 0

=> 2x^2-30.8x + 116.16 = 0

Solving above quadratic equation using quadratic formula

General form of quadratic equation is  

ax^2 +bx +c = 0

And quadratic formula for getting roots of quadratic equation is  

x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}

As equation is 2x^2-30.8x + 116.16 = 0, in our case

a = 2 ,  b = -30.8 and c = 116.16

Calculating roots of the equation we get

x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}

x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{(30.8\pm29.33)}4

x=\frac{(30.8+29.33)}{4}

x=\frac{(30.8-29.33)}{4}

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,  

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0
3 years ago
Which best describes Imara’s error?
Sati [7]
<h2>Answer:</h2>

The statement that best describes Imara's error is:

                         Option: D

  D). She did not find the side lengths of the square with an area of 625.

<h2>Step-by-step explanation:</h2>

Imara correctly did the previous calculation.

i.e. she correctly determined the area of square with side length 20 units (as 400 square units) and 15 units (i.e. 225 square units)

But when she sum the area of two squares then it won't give the length of hypotenuse it would give the  area of a square.

                      Hence, the correct answer is:

                              Option: D

7 0
3 years ago
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