Well, variables are stuff like x and y because they can represent a number. They are variable in an equation. so if you have (3x^3)+(5X^2)+Y+9 then your variables are x X and Y (im assuming the capital X is there and not a typo) if that was a typo and meant to be lowercase, then its just a 2 variable with the x and y
We are given a graph of a quadratic function y = f(x) .
We need to find the solution set of the given graph of a quadratic function .
<em>Note: Solution of a function the values of x-coordinates, where graph cut the x-axis.</em>
For the shown graph, we can see that parabola in the graph doesn't cut the x-axis at any point.
It cuts only y-axis.
Because solution of a graph is only the values of x-coordinates, where graph cut the x-axis. Therefore, there would not by any solution of the quadratic function y = f(x).
<h3>So, the correct option is 2nd option :∅.</h3>
Well first of you need to know that on a straight line there should be 180 degrees. Also a triangle has 180 degrees in total. Now if this is to scale then you can always measure the angle BCA and explain how you took that away from 180 to get whatever. Assuming otherwise i don't know how one can actually complete this question without any measurements, at least one and it would be something anyone can complete. Even if you didn't have anything it should be a equilateral triangle or isosceles. That way you can work out the inside sides than the exterior. But since it's not, I'm not to sure.
The numbers as powers of 5 are 5^-1, 5^-2, 5^-3 and 5^0
<h3>How to rewrite the numbers as a power of 5?</h3>
The numbers are given as:
• 0.2
• 0.04
• 125^-1
• 15^0
<u>Number 1: 0.2</u>
Express as fraction
1/5
Apply the power rule of indices
5^-1
<u>Number 2: 0.04</u>
Express as fraction
1/25
Express 25 as 5^2
1/5^2
Apply the power rule of indices
5^-2
<u>Number 3: 125^-1</u>
Express as fraction
1/125
Express 125 as 5^3
1/5^3
Apply the power rule of indices
5^-3
<u>Number 4: 15^0</u>
Evaluate the exponent
15^0 = 1
Express 1 as 5^0
15^0 = 5^0
Hence, the numbers as a power of 5 are 5^-1, 5^-2, 5^-3 and 5^0
Read more about exponents at
brainly.com/question/847241
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Add two 0's to 14.7 making 14.700