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baherus [9]
3 years ago
10

​Al2(SO4)3 + BaCl2 BaSO4 + AlCl3

Physics
1 answer:
dangina [55]3 years ago
6 0

Hey there!

Al₂(SO₄)₃ + BaCl₂ → BaSO₄ + AlCl₃

First balance SO₄ since it is a polyatomic ion.

3 on the left, 1 on the right. Add a coefficient of 3 in front of BaSO₄.

Al₂(SO₄)₃ + BaCl₂ → 3BaSO₄ + AlCl₃

Balance Ba.

1 on the left, 3 on the right. Add a coefficient of 3 in front of BaCl₂.

Al₂(SO₄)₃ + 3BaCl₂ → 3BaSO₄ + AlCl₃

Balance Cl.

6 on the left, 3 on the right. Add a coefficient of 2 in front of AlCl₃.

Al₂(SO₄)₃ + 3BaCl₂ → 3BaSO₄ + 2AlCl₃

Balance Al.

2 on the left, 2 on the right. Already balanced.

Our final balanced equation:

Al₂(SO₄)₃ + 3BaCl₂ → 3BaSO₄ + 2AlCl₃

Hope this helps!

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3 years ago
Where are metalloids found on the periodic table
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to the right of the post transition metals and to the left of the non metals.

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Now suppose that the Earth had the same mass and radius as it currently does, but all of the mass was concentrated into a thin (
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The force of gravity at the shell will be extremely great on me due to the huge mass collapsed into the small radius.

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Explanation:

For the collapsed earth:

mass = 5.972 × 10^24 kg

radius = 1 ft

according to Newton's gravitation law, the force of gravity due to two body with mass is given as

Fg = GMm/R^{2}

Where Fg is the gravitational force between the two bodies.

G is the gravitational constant

M is the mass of the earth

m is my own mass

R is the distance between me and the center of the earths in each case

For the case where I stand on the shell:

radius R will be 1 ft

Fg = GMm/1^{2}

Fg = GMm

For the case where I stand stand inside the shell, lets say I'm positioned at the center of the shell. The force of gravity due to my mass will be balanced out by all other masses around due to the shell of the hollow earth. This cancelling will produce a weightless feeling on me.

3 0
3 years ago
A solenoid of length 5.0 cm has a cross sectional area of 1.0 cm2 and has 300 uniformly spaced turns. The solenoid is wrapped in
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The calculated mutual inductance is 8.544 x 10⁻⁵ H.

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Length of the solenoid= 5.0 cm

Area of cross-section=1.0 cm²

no of spaced turns=300 turns

turns of insulated wire=180 turns

Mutual inductance (M) = μ₀μr N1N2 A/ L

                                     =(4xπx 10⁻⁷) x (6.3 x 10⁻³) x 300 x 180 x 1/ 5

                                     =79.12 x 10⁻¹⁰ x 54000 / 5

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hence, the mutual inductance is 8.544 x 10⁻⁵ H.

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4 0
1 year ago
At the end of the adiabatic expansion, the gas fills a new volume V₁, where V₁ &gt; V₀. Find W, the work done by the gas on the
tino4ka555 [31]

Answer:

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Explanation:

An adiabatic process refers to one where there is no exchange of heat.

The equation of state of an adiabatic process is given by,

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=\frac{p_0V_0-p_1V_1}{\gamma-1}

4 0
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