1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
maria [59]
3 years ago
15

Now suppose that the Earth had the same mass and radius as it currently does, but all of the mass was concentrated into a thin (

1 ft. thick) hollow spherical shell below your feet. Also suppose there was a small hole in the shell, just big enough four you to fit through. Compare the force of gravity on you outside the shell to the force of gravity if you stepped inside the shell.
Physics
1 answer:
KiRa [710]3 years ago
3 0

Answer:

The force of gravity at the shell will be extremely great on me due to the huge mass collapsed into the small radius.

<em>At the center of the shell, the gravitational forces all around should cancel out, giving me a feeling of weightlessness; which will be a lesser force compared to that felt while standing on the shell.</em>

<em></em>

Explanation:

For the collapsed earth:

mass = 5.972 × 10^24 kg

radius = 1 ft

according to Newton's gravitation law, the force of gravity due to two body with mass is given as

Fg = GMm/R^{2}

Where Fg is the gravitational force between the two bodies.

G is the gravitational constant

M is the mass of the earth

m is my own mass

R is the distance between me and the center of the earths in each case

For the case where I stand on the shell:

radius R will be 1 ft

Fg = GMm/1^{2}

Fg = GMm

For the case where I stand stand inside the shell, lets say I'm positioned at the center of the shell. The force of gravity due to my mass will be balanced out by all other masses around due to the shell of the hollow earth. This cancelling will produce a weightless feeling on me.

You might be interested in
A seesaw is 4.0m long with a pivot at its midpoint. A boy who weighs 400N sits at a distance of 1.5m from the pivot. His sister
bezimeni [28]

Answer:

the girl must sit 2 cm from the pivot at the opposite end of the seesaw.

Explanation:

Given;

length of the seesaw, L = 4.0 m

weight of the boy, W₁ = 400 N

position of the boy from the pivot, d₁ = 1.5 m

weight of her sister, W₂ = 300 N

First, make a sketch of this information given;

                 0---0.5m---------------------Δ--------------------------4m

                         ↓<--------1.5m-------> <---------x--------->↓

                        400 N                                          300N

Apply the principle of moment about the pivot, to determine the value of x;

Sum of anticlockwise moment = sum of clockwise moment

400(1.5) = 300(x)

600 = 300x

x = 600/300

x = 2 cm

Thus, the girl must sit 2 cm from the pivot at the opposite end of the seesaw.

8 0
3 years ago
At a rock concert, the sound intensity 1.0 m in front of the bank of loudspeakers is 0.10 W/m². A fan is 30 m from the loudspeak
Klio2033 [76]

To solve this problem we will apply the concepts related to the Area, the power and the proportionality relationships between intensity and distance.

The expression for sound power is,

P = AI

Here,

A = Area

I = Intensity

P = Power

At the same time the area can be written as,

A = \frac{\pi d^2}{4}

Now the intensity is inversely proportional to the square of the distance from the source, then

I \propto \frac{1}{r^2}

The expression for the intensity at different distance is

\frac{I_1}{I_2}= \frac{r^2_2}{r_1^2}

Here,

I_1 = Intensity at distance 1

I_2 = Intensity at distance 2

r_1 = Distance 1 from light source

r_2 = Distance 2 from the light source

If we rearrange the expression to find the intensity at second position we have,

I_2 = I_1 (\frac{r_1^2}{r_2^2})

If we replace with our values at this equation we have,

I_2 = (0.10W/m^2)(\frac{1.0m^2}{30.0m^2})

I_2 = 1.11*10^{-4} W/m^2

Now using the equation to find the area we have that

A = \frac{\pi (8.4*10^{-3}m)^2}{4}

A = 5.5*10^{-5}m^2

Finally with the intensity and the area we can find the sound power, which is

P = AI

P = (5.5*10^{-5}m^2)(1.11*10^{-4}W/m^2)

P = 6.1*10^{-9}J/s

Power is defined as the quantity of Energy per second, then

E = 6.1*10^{-9}J

8 0
3 years ago
What is the frequency of a wave if the wave speed is 24 m/s and the wavelength is 2m?
fredd [130]
The formula F=velocity/wavelength
F=24/2
F=12 Hz
4 0
3 years ago
Read 2 more answers
A particle moves horizontally in uniform circular motion, over a horizontal xy plane. At one instant, it moves through the point
Alexus [3.1K]

Answer:

(2.5,0)

Explanation:

The particle can be described by the following equations:

x=Rsin(-\omega t)+2.5\\y=Rcos(-\omega t)\\\frac{dx}{dt}=-\omega Rcos(-\omega t)\\\frac{dy}{dt}=\omega Rsin(-\omega t)\\\frac{d^2x}{dt^2}=-\omega^2Rsin(-\omega t)\\\frac{d^2y}{dt^2}=-\omega^2Rcos(-\omega t)

For R = 2.5, ω = 2 and t = 0:

x=2.5\\y=2.5\\\\\frac{dx}{dt}=-5\\ \frac{d^2y}{dt^2}=-10

The center of the circle would be at point (2.5,0)

5 0
3 years ago
Which organs are used in reproduction?
Anestetic [448]

Answer:

d. ovaries, uterus, and Fallopian tubes

Explanation:

8 0
3 years ago
Other questions:
  • The two types of vitamins are fat and water soluble?
    14·1 answer
  • The image shows a diagram. which descriptions best fit the labels
    14·2 answers
  • Near the surface of Earth, acceleration due to gravity is 9.8 m/s2. Remember the formula: velocity = acceleration x time. Imagin
    6·2 answers
  • A simple model for a person running the 100 m dash is to assume the sprinter runs with constant acceleration until reaching top
    11·1 answer
  • A point charge is placed at the center of a spherical Gaussian surface. The electricflux ΦEischangedif(a) a second point charge
    5·1 answer
  • How do we prove the earth is round? What evidence do we have and reasoning?
    13·2 answers
  • A 2 column by 3 row table. Column 1 is titled Planet A with the following entries: Atmosphere is mostly carbon dioxide, Surface
    12·1 answer
  • Compare the signs of ƒ for lenses and mirrors.
    13·2 answers
  • 4. A desk with a mass of 10 kg is pushed across a floor with an acceleration of 4 m/s?. What
    14·2 answers
  • The equivalent resistance of a series combination of resistors is always greater than any individual resistance
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!