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Mkey [24]
3 years ago
8

When light waves hit ice, most of them bounce off and radiate back into space. Because of this, it can be said that ice is a(n)

Physics
2 answers:
Softa [21]3 years ago
8 0
Reflective~~~~~~~~~~~~~~~~~~~~~~
kirill [66]3 years ago
8 0

<u>Answer;</u>

Reflective surface

<u>Explanation;</u>

  • Reflection is one of the property of a wave that occurs when a wave hits a boundary which is a reflective surface. The wave bounces off upon hitting the reflective boundary, such that the angle of incidence is equal to the angle of reflection.
  • Therefore, ice is an example of a reflective surface as light waves bounces off and radiate back when they hit the surface of the ice.
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Pam, wearing a rocket pack, stands on frictionless ice. She has a mass of 49 kg. The rocket supplies a constant force for 22.0 m
ss7ja [257]

Answer:

Magnitude of the force is 4350N

Explanation:

As the woman accelerates at a distance of 22 m to go from rest to 62.5 m / s, we can use the kinematics to find the acceleration

v² = v₀² + 2 a x

v₀ = 0

a = v² / 2x

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 a = 88.78m/s²

the time you need to get this speed

     v = v₀ + a t

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Let's caculate the magnitude of the force

F = ma

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= 4350.22

≅ 4350N

Magnitude of the force is 4350N

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4 0
3 years ago
N a laboratory test of tolerance for high acceleration, a pilot is swung in a circle 11.5 m in diameter. it is found that the pi
Deffense [45]
<span>59.027m/s^2 Centripetal force is give by F = mv^2/r Since F = ma The acceleation accoiated with this centripetal force is a=v^2/r the radius is found by r=d/2=5.75m velocity is found by v=d/t distance is the circumference of the circle c=pi*d=11.5*3.14=36.11m time=60s/30.6rpm=1.96s v=36.11/1.96=18.423m/s plugging this back in to a=v^2/r=(18.423m/s)^2/5.75m=59.027m/s^2</span>
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5 0
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Rufina [12.5K]

Answer:

3/4 of 12 = 16

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Those are the answers based on how your question sounded

Explanation:

6 0
3 years ago
Read 2 more answers
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