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inessss [21]
4 years ago
5

Solve -5 square root x =15

Mathematics
1 answer:
Nezavi [6.7K]4 years ago
3 0

Answer:

x = 9.

Step-by-step explanation:

-5 square root x =15

divide both sides by -5:

√x = 15/-5 = -3

Squaring both sides:

x = 9.

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Find the equation of a line with the following information. Passes through (4,3) and is perpendicular to the straight line 3x-2y
Natasha_Volkova [10]
3x - 2y + 4 = 0
-2y = -3x - 4
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y = mx + b
slope(m) = -2/3
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3 = -2/3(4) + b
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3 + 8/3 = b
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5 0
3 years ago
Solution A is an $80\%$ acid solution. Solution B is a $30\%$ acid solution. (a) Find the amount of Solution A (in mL) that must
Irina-Kira [14]

Answer:

(a)2000\text{ ml} (b)40\text{ ml and }60\text{ ml} (c)NO

Step-by-step explanation:

GIVEN: Solution A is an \$80\% acid solution. Solution B is a \$30\% acid solution.

TO FIND: (a) Find the amount of Solution A (in mL) that must be added to 500 \text{ml} of Solution B in order to produce a 70\% acid solution. (b) Find the amount of Solution A and Solution B (in mL) that can be combined in order to form a 100 \text{ml} solution that is 50\% acid. (c) Does there exist a combination of Solution A and Solution B that is 90\% acid.

SOLUTION:

(a)

Let total amount of solution A added be x

Total amount of mixture =500+x\text{ ml}

As resulting solution is  70\% acid solution.

Amount of acid in final solution is sum of acid in both solutions

\frac{70}{100}(500+x)=\frac{80}{100}x+\frac{30}{100}\times500

35000+70x=80x+15000

x=2000\text{ ml}

(b)

Let amount of Solution A be x\text{ ml}

Amount of solution B =100-x\text{ ml}

As resulting solution is 50\% acidic solution

Amount of acid in final solution is sum of acid in both solutions

\frac{50}{100}\times100=\frac{80}{100}x+\frac{30}{100}(100-x)

5000=80x+3000-30x

50x=2000

x=40\text{ ml}

Amount of solution B =100-40=60\text{ ml}

(c)

No as concentration of final solution can not be greater than one with higher concentration.

7 0
4 years ago
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