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3 years ago

What are three equivalent ratios for 3 : 3 1/2

Mathematics

1 answer:

jolli1 [7]3 years ago

7 0

Answer:

6 : 7
9 : 10 1/2
12 : 14

Step-by-step explanation:

Multiply the given values by any number you like. The results will be integers if the number is even.

×2 gives 3×2 : (3 1/2)×2 = 6 : 7

×3 gives 3×3 : (3 1/2)×3 = 9 : 10 1/2

×4 gives 3×4 : (3 1/2)×4 = 12 : 14

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Now we can simplify the ratio/fraction
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3 years ago

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hichkok12 [17]

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3 years ago

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umka21 [38]

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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2 years ago

Find the six trigonometric function values for angle ∅ where its adjacent side is -9 and its hypotenuse is 41. (Theta is located

arsen [322]

Check the picture below.

$\bf \textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\sqrt{41^2-(-9)^2}=b\implies \sqrt{1681-81}=b\\\\\\ \sqrt{1600}=b\implies 40=b\\\\
-------------------------------$

$\bf sin(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{hypotenuse}{41}}\qquad~~ cos(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{hypotenuse}{41}}\qquad~~ tan(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{adjacent}{-9}}
\\\\\\
csc(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{opposite}{40}}\qquad ~~sec(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{adjacent}{-9}}\qquad ~~cot(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{opposite}{40}}$

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3 years ago