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frez [133]
3 years ago
15

There were 15 students running in a race. How many different arrangements of first, second, and third place are possible?

Mathematics
1 answer:
viktelen [127]3 years ago
7 0

Answer:

The area 2730 possible arrangements of first, second, and third place.

Step-by-step explanation:

The order in which the students finish is important. For example A, B and C is a different finishing order(outcome) than B, A and C. So we use the permutations formula to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

P_{(n,x)} = \frac{n!}{(n-x)!}

In this question:

3 from a set of 15. So

P_{(15,3)} = \frac{15!}{(15-3)!} = 2730

The area 2730 possible arrangements of first, second, and third place.

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