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mars1129 [50]
3 years ago
12

What is the slope. please hurry up​

Mathematics
1 answer:
Wewaii [24]3 years ago
6 0

Answer:

The slope is 1/2

Step-by-step explanation:

m=y²-y¹/x²-x¹

m=2-1/4-2

m=1/2

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Solve the formula 27a + 1/3 * b = 4 for a.
Aneli [31]

Answer:

a = 4/27 - b/81

Step-by-step explanation:

27a + 1/3 * b = 4

Subtract the term with b from both sides.

27a = 4 - 1/3 *b

Divide both sides by 27.

a = 4/27 - 1/81 * b

a = 4/27 - b/81

4 0
2 years ago
Read 2 more answers
Since it is given that AB ≅ AC, it must also be true that AB = AC. Assume ∠B and ∠C are not congruent. Then the measure of one a
mrs_skeptik [129]
<span>Since it is given that AB ≅ AC, it must also be true that AB = AC. Assume ∠B and ∠C are not congruent. Then the measure of one angle is greater than the other. If m∠B > m∠C, then AC > AB because of the triangle parts relationship theorem. For the same reason, if m∠B < m∠C, then AC < AB. This is a contradiction to what is given. Therefore, it can be concluded that 


Answer: Angle (B) is Congruent to Angle (C)

Hope it helps
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6 0
3 years ago
3 On a coordinate grid, the location of a lighthouse is at L, and the location of a buoy is at B. At noon, a ship is at the midp
Zarrin [17]

Answer:

(\frac{1}{2}, 2)

Step-by-step explanation:

Using the midpoint formula, M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}), we can find the coordinates that represents the position of the ship at noon.

Let L(-4, 7) = (x_1, y_1) (given on the coordinate plane)

B(5, -3) = (x_2, y_2) (given also)

Plug in the values into the formula and solve as follows:

M(\frac{-4 + 5}{2}, \frac{7 +(-3)}{2})

M(\frac{1}{2}, \frac{7 - 3}{2})

M(\frac{1}{2}, \frac{4}{2})

M(\frac{1}{2}, 2)

Position of the ship at noon is best represented at (\frac{1}{2}, 2)

5 0
3 years ago
2
goldfiish [28.3K]

Answer:

The volume of can A is half the volume of can B.

Step-by-step explanation:

Given

Can A and Can B

Required

The true statement

For Can A, we have:

h =8

r = 0.5

The volume is:

Volume = \pi r^2h

This gives:

V_A = \pi * 0.5^2 * 8

V_A = \pi * 2

V_A = 2\pi

For Can B, we have:

h =4

r = 1

The volume is:

Volume = \pi r^2h

This gives:

V_B = \pi * 1^2 * 4

V_B = \pi  * 4

V_B = 4\pi

So, we have:

V_A = 2\pi

V_B = 4\pi

By comparison, (d) is correct

4 0
3 years ago
Please help this was due today
Aleksandr [31]

Answer:

Why didn't u do it ?

Step-by-step explanation:

i know dumb question but i got points so i'm a OK if u were wondering

8 0
2 years ago
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