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3 years ago

14

What is the perimeter of the inside of the track if the distance between two parallel straight parts of the track is 60 meters a

nd they are each 106 meters long?

1 answer:

alina1380 [7]3 years ago

8 0

It is most likely
332 meters

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Depreciation is the decrease or loss in value of an item due to age, wear, or market conditions. We usually consider depreciatio

Alik [6]

Answer:The value of the bulldozer after 3 years is $121950

Step-by-step explanation:

We would apply the straight line depreciation method. In this method, the value of the asset(bulldozer) is reduced linearly over its useful life until it reaches its salvage value. The formula is expressed as

Annual depreciation expense =

(Cost of the asset - salvage value)/useful life of the asset.

From the given information,

Useful life = 23 years

Salvage value of the bulldozer = $14950

Cost of the new bulldozer is $138000

Therefore

Annual depreciation = (138000 - 14950)/ 23 = $5350

The value of the bulldozer at any point would be V. Therefore

5350 = (138000 - V)/ t

5350t = 138000 - V

V = 138000 - 5350t

The value of the bulldozer after 3 years would be

V = 138000 - 5350×3 = $121950

4 0

3 years ago

What are questions 10-15?

AfilCa [17]

Answer:

10. 105

11. 75

12. 75

13. 105

14. 75

15. 105

Step-by-step explanation:

Notice that 75? Anything that is adjacent (has a common vertex like 75º) to the vertex is a linear pair. here is an example below:

Since there is only THAT 75, you must find the supplementary angle (adds up to 180). and remember in order to get a supplementary angle it has to be a STRAIGHT LINE and HAS TO EQUAL 180. (4, 1 in your image)

180 - 75 = 105.

and also it's also a linear pair so it reflects too which makes things a lot easier!

So, if 4 is 75 and it reflects, then that means 2 is also 75. 1 is 105 and it reflects so 3 has to be 105. and the same for the rest of the numbers.

Hope this makes sense

~R3VO

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2 years ago

If t=0 in 1980, find the value of A. Round answer to the nearest million.

balu736 [363]

P=Ae^kt

225 = 210 * e^(k*(1990-1980)

225/210=e^10k ln(225/210)=10k

k=ln(225/210)/10=0.0069

P = 210*e^(0.0069t)

for 2000 ===> t = 2000-1980=20

P = 210*e^(0.0069*20)

P=241.0749=241

4 0

3 years ago

What is the value of c in the equation below? 2^-4(2^2)=a^b=c

Triss [41]

Answer:

The answer is option 4.

Step-by-step explanation:

You have to use Indices Law,

${a}^{m} \times {a}^{n} = {a}^{m + n}$

${a}^{ - n} = \frac{1}{ {a}^{n} }$

So for this question :

${2}^{ - 4} \times {2}^{2}$

$= {2}^{ - 4 + 2}$

$= {2}^{ - 2}$

${a}^{b} = c \\ c = {2}^{ - 2}$

$c = \frac{1}{ {2}^{2} }$

$c = \frac{1}{4}$

5 0

2 years ago

Evaluate the expression below:<br> bb-a)<br> for b = 8, a = 4<br><br><br> HS Math

kondaur [170]

The answer will be 60 because 8*8=64 then subtract 4

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2 years ago

Read 2 more answers