How to find the area of the shaded region

The ratio of the number of boys to the number of girls in a school is 5 : 7. If there are 600 students in the school, how many a

enot [183]

Answer:

350 of the students are girls.

Step-by-step explanation:

5+7 = 12

600/12 = 50

50 x 7 = 350

4 0

3 years ago

Factorise completely x^3+6x^2+3x-10

natima [27]

Answer:Solution

(

−

1

)

(

+

2

)

(

+

5

)

(

x

−

1

)

(

x

+

2

)

(

x

+

5

)

(x−1)(x+2)(x+5)

Step-by-step explanation:

How to solve your problem

3

+

6

2

+

3

−

1

0

x

3

+

6

x

2

+

3

x

−

10

x3+6x2+3x−10

Grouping

1

Find one factor

Factor by grouping

4 0

2 years ago

Read 2 more answers

The sum of three numbers is 27 the second number is three times the first while the third is twice the first find their average

Leviafan [203]

Answer:

9

Step-by-step explanation:

x = first number

3x = second number

2x = third number

27 = x + 3x+ 2x

27 = 6x

x=4.5 (first number)

3(4.5) = 13.5 (second number)

2(4.5) = 9 (third number)

(4.5 + 13.5 + 9) /3 = 9

Wow after doing all that I realized that all you had to do was 27/3 since there's 3 numbers.

6 0

3 years ago

Solve the inequality x + 2 > 6.

Aloiza [94]

Answer:

x > 4

Step-by-step explanation:

x + 2 > 6

-2 -2

x > 4

7 0

3 years ago

Read 2 more answers

Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed

vlabodo [156]

Answer:

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm)

Step-by-step explanation:

Our sample size is 11.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 11-1 = 10$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 10 and 0.025 in the two-sided t-distribution table, we have $T = 1.812$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{4}{\sqrt{11}} = 1.2060$

Now, we multiply T and s

$M = Ts = 1.812*1.2060 = 2.19/tex]For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is[tex]L = 97 - 2.19 = 94.81 = 94.8$ cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

$L = 97 + 2.19 = 99.19 = 99.2$ cm

So

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm).

7 0

3 years ago