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3 years ago

If t=0 in 1980, find the value of A. Round answer to the nearest million.

Mathematics

1 answer:

balu736 [363]3 years ago

4 0

P=Ae^kt

225 = 210 * e^(k*(1990-1980)

225/210=e^10k ln(225/210)=10k

k=ln(225/210)/10=0.0069

P = 210*e^(0.0069t)

for 2000 ===> t = 2000-1980=20

P = 210*e^(0.0069*20)

P=241.0749=241

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