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3 years ago

What is 1000 rounded to the nearest ten?

Mathematics

1 answer:

Serga [27]3 years ago

5 0

Its 1000 cause its all zeros

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“encontrar la integral indefinida y verificar el resultado mediante derivación”

Oliga [24]

$I=\displaystyle\int\frac x{(1-x^2)^3}\,\mathrm dx$

Haz la sustitución:

$y=1-x^2\implies\mathrm dy=-2x\,\mathrm dx$

$\implies I=\displaystyle-\frac12\int\frac{\mathrm dy}{y^3}=\frac1{4y^2}+C=\frac1{4(1-x^2)^2}+C$

Para confirmar el resultado:

$\dfrac{\mathrm dI}{\mathrm dx}=\dfrac14\left(-\dfrac{2(-2x)}{(1-x^2)^3}\right)=\dfrac x{(1-x^2)^3}$

$I=\displaystyle\int\frac{x^2}{(1+x^3)^2}\,\mathrm dx$

Sustituye:

$y=1+x^3\implies\mathrm dy=3x^2\,\mathrm dx$

$\implies I=\displaystyle\frac13\int\frac{\mathrm dy}{y^2}=-\frac1{3y}+C=-\frac1{3(1+x^3)}+C$

(Te dejaré confirmar por ti mismo.)

$I=\displaystyle\int\frac x{\sqrt{1-x^2}}\,\mathrm dx$

Sustituye:

$y=1-x^2\implies\mathrm dy=-2x\,\mathrm dx$

$\implies I=\displaystyle-\frac12\int\frac{\mathrm dy}{\sqrt y}=-\frac12(2\sqrt y)+C=-\sqrt{1-x^2}+C$

$I=\displaystyle\int\left(1+\frac1t\right)^3\frac{\mathrm dt}{t^2}$

Sustituye:

$u=1+\dfrac1t\implies\mathrm du=-\dfrac{\mathrm dt}{t^2}$

$\implies I=-\displaystyle\int u^3\,\mathrm du=-\frac{u^4}4+C=-\frac{\left(1+\frac1t\right)^4}4+C$

Podemos hacer que esto se vea un poco mejor:

$\left(1+\dfrac1t\right)^4=\left(\dfrac{t+1}t\right)^4=\dfrac{(t+1)^4}{t^4}$

$\implies I=-\dfrac{(t+1)^4}{4t^4}+C$

4 0

3 years ago

VERY URGENT PLEASE HELP

ira [324]

Use the tutor app to help you he or she will help you for each problem.

6 0

3 years ago

-6<2c-4<14 compound inequality

Vladimir [108]

Answer:

-1 < c < 9

Step-by-step explanation:

-6<2c-4<14

Add 4 to all sides

-6+4<2c-4+4<14+4

-2<2c<18

Divide by 2

-2/2<2c/2<18/2

-1 < c < 9

8 0

3 years ago

Graph the system of equation -9x + 3y = 27 8x + 8y =40

kirill [66]

(-1, 6) is your answer

6 0

2 years ago

Find the quotient of quantity of 3 times x to the 3rd power plus 9 times x to the 2nd power minus 6 times x all over negative 3

ki77a [65]

-x^2 -3x + 2
------------------------------
-3x ) 3x^3 + 9x^2 - 6x
3x^3
9x^2
-6x

answer is -x^2 - 3x + 2

3 0

3 years ago

Read 2 more answers