1 Substitute
y
=
2
x
−
10
y=2x−10 into
y
=
4
x
−
8
y=4x−8.
2
x
−
10
=
4
x
−
8
2x−10=4x−8
2 Solve for
x
x in
2
x
−
10
=
4
x
−
8
2x−10=4x−8.
x
=
−
1
x=−1
3 Substitute
x
=
−
1
x=−1 into
y
=
2
x
−
10
y=2x−10.
y
=
−
12
y=−12
4 Therefore,
x
=
−
1
y
=
−
12
x=−1
y=−12
<u>Answer:</u>
The answer is B -->
<u>How I got that:</u>
<u />
These are really easy, you're simply looking for numbers that you can factor down. Like here:
I took:
and saw that I could factor out 4 from the denominator:
and then I canceled out the common factor (4 because its on both sides):
And there ya go!
<em>~That's All Folks~</em>
<em>-Siascon</em>
Answer:
6
Step-by-step explanation:
Let . We know the formula for the sum of an arithmetic sequence is:
Where n is the number term you are finding the sum up to, a1 is the first term, and an is the nth term. We can substitute what we have:
The formula to find the nth term of an arithmetic series is:
Where d is the common difference. Again, we can plug in what we have;
Answer:
83
Step-by-step explanation:
78+ (72÷9) -3
72÷9=8
78+8=86
86-3=83