Question

Solve the equation with quadratic formula 15g2+17g-110=0

Answer 1

Answer:

The solution of the quadratic equation $15g^{2}+ 17g - 110 = 0$ are $g = (-\frac{10}{3}, \frac{11}{5})$.

Step-by-step explanation:

The quadratic equation is: $15g^{2}+ 17g - 110 = 0$

Use factorization method to determine the roots of g.

Factor the equation $15g^{2}+ 17g - 110 = 0$ as follows:

$15g^{2}+ 17g - 110 = 0\\15g^{2}+ 50g - 33g - 110 = 0\\5g (3g + 10) - 11 (3g + 10) = 0\\(5g - 11) (3g + 10) = 0$

First substitute $(5g - 11)$ equal to 0 and solve for g as follows:

$(5g - 11)=0\\5g=11\\g=\frac{11}{5}$

Now, substitute $(3g + 10)$equal to 0 and solve for g as follows:

$(3g + 10)=0\\3g=-10\\g=-\frac{10}{3}$

So, the solution of the quadratic equation $15g^{2}+ 17g - 110 = 0$ are $g = (-\frac{10}{3}, \frac{11}{5})$