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2 years ago

Solve the equation 6(3x + 4) = 4x -4. 10 7 0x = -2 Ox=2

1 answer:

5 0

-2 is the answer! Remove the parentheses then move the terms. After that, collect the terms and calculate. Lastly, divide both sides.

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A rectangular computer table measures 30 inches by 50 inches. We need to cover it with square tiles. What is the side length of

jekas [21]

Answer:

a) 10*10 inch, b)yes, c) 15

Step-by-step explanation:

we need to calculate the Greatest Common Factor between 30 and 50

$30 = 2 \times 3 \times 5 \\ 50 = 2 \times 5 \times 5 \\ GCM = 2 \times 5 = 10$

then, the square tiles will be 10 inch *10 inch

b) it will change because they don't need to have the largest slab possible so they will use any other comon factor with a size they consider correct for the cheese.

$30 \div 10 = 3 \\ 50 \div 10 = 5 \\ 3 \times 5 = 15$

15 squares of 10inch*10inch of cheese could be cut.

6 0

3 years ago

Read 2 more answers

Will give brainliest, Please explain how you got your answer!

Tpy6a [65]

2x + 14 + 6y (multiply everything by 2)

6 0

2 years ago

How many times does 12 go into 648

frozen [14]

12 can go into 648 54 times. :)

8 0

2 years ago

Read 2 more answers

Suppose you just received a shipment of ten televisions. two of the televisions are defective. if two televisions are randomly

amid [387]

Try this solution:

1. for probability of both televisions work:

$P_{2w}=\frac{C^2_8}{C^2_{10}}=\frac{7*8}{9*10}=0.6(2)$

2. for probability of at least on is defective (it means, the sum = one is defective and two are defective):

$P_{1d}=\frac{C^1_2C^1_8}{C^2_{10}}=\frac{4*8}{9*10}=0.3(5)$ - for P(1defective);

$P_{2d}=\frac{C^2_2}{C^2_{10}}=\frac{2}{9*10}=0.0(2)$ - for P(2defective);

totaly for at least one is defective:

$P_{at \ least \ 1 \ d}=P_{1d}+P_{2d}=\frac{16}{45} +\frac{1}{45} =0.3(7)$

5 0

3 years ago

Can someone help me out, please?

GenaCL600 [577]

Rectangle, triangle, and I believe square

3 0

3 years ago