Answer:
x = 4 + sqrt(5) or x = 4 - sqrt(5)
Step-by-step explanation:
Solve for x:
(x - 4)^2 = 5
Take the square root of both sides:
x - 4 = sqrt(5) or x - 4 = -sqrt(5)
Add 4 to both sides:
x = 4 + sqrt(5) or x - 4 = -sqrt(5)
Add 4 to both sides:
Answer: x = 4 + sqrt(5) or x = 4 - sqrt(5)
Area of a square = (side)² or = (side*side)
Area of the square = (8 inch)² = 8*8 inch² = 64 inch²
Answer is 64 sq. in.
Answer:
C. △ABC ~ △DEF
Step-by-step explanation:
There are two geometry symbols among the choices.
~ is used for indicating similarity.
≅ is used for congruency.
Statement △ABC ~ △DEF means that triangle ABC is similar to triangle DEF. There is no triangle symbol in front of DEF in the picture, but I am assuming this was a typo.
Here is
the solution for this specific problem:
<span>Based from the graph,
the curve will intersect itself at the y-axis, i.e. x = 0. </span><span>
</span><span>t^3 - 6t = 0 </span><span>
<span>t(t^2 -
6) = 0 </span>
<span>t = 0 or
t = ± √6 </span>
<span>dx/dt =
3t^2 - 6 </span>
<span>dy/dt =
2t </span>
<span>dy/dx =
2t/(3t^2 - 6) </span>
<span>@ t = 0,
dy/dx = 0. </span>
<span>x = 0, y
= 0 </span>
<span>y = 0 </span>
<span>@ t = √6,
dy/dx = 2√6/12 = √6/6 </span>
<span>x = 0, y
= 6 </span>
<span>y - 6 =
(√6/6) x </span>
<span>y =
(√6/6)x + 6 </span>
<span>@ t =
-√6, dy/dx = -2√6/12 = -√6/6 </span>
<span>x = 0, y
= 6 </span>
<span>y - 6 =
(-√6/6) x </span>
y = (-√6/6)x
+ 6</span>
So the equations of the tangent
line at the point where the curve crosses itself are: <span>y = (√6/6)x + 6 and
</span>y = (-√6/6)x + 6. I am hoping that these answers have
satisfied your queries and it will be able to help you in your endeavors, and
if you would like, feel free to ask another question.
